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Nezavi [6.7K]
3 years ago
12

Algebra question please help and show work! :)

Mathematics
1 answer:
8_murik_8 [283]3 years ago
4 0
The answer to the question is c
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If cos(2/3x+20)°=sin(2x−10)°, find the acute angles of the corresponding right triangle.
adell [148]

Answer:

A = 40°

B = 50°

Step-by-step explanation:

If cos A = sin B, then A + B = 90

So, 2x/3 + 20  + 2x - 10 = 90

      2x + 60 + 6x - 30 = 270

               8x + 30 = 270

                       8x = 240

                          x = 30

2x/3 + 20 = 60/3 + 20 = 20 + 20 = 40

2x - 10 = 2(30) - 10 = 60 - 10 = 50  or  90 - 40 = 50

       

7 0
3 years ago
4x + 3y =4 2x - y =7 in substitution
IRINA_888 [86]
The answer is (4x+3y=4 2x-7=7: 5/2 and y=-2) hope it helps and have a good day!
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3 years ago
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konstantin123 [22]
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2.71 goes with -2.71

-(-2.71) goes with 2.71
7 0
3 years ago
The measurements of a box are doubled. What happens to its volume?
jek_recluse [69]
V=LWH
if each is doubled
V=2L2W2H
V=2*2*2*LWH
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8 0
3 years ago
Read 2 more answers
What value of x makes this equation true? 12x - 15 = 6x - 3
djverab [1.8K]

Answer:

2

Step-by-step explanation:

12 x - 15 = 6x - 3

12 x - 6x = 15 - 3

6x = 12

x = 12/6 = 2

3 0
2 years ago
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