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Answer:
The required probability is 0.0155.
Step-by-step explanation:
We are given that the one-year survival rate for pancreatic cancer is 20%.
Of 12 people diagnosed with pancreatic cancer at one hospital, 6 survived one year.
The above situation can be represented through binomial distribution;
where, n = number of trials (samples) taken = 12 people
r = number of success = 6 survived
p = probability of success which in our question is probability of
one-year survival rate for pancreatic cancer, i.e; p = 20%
Let X = <u><em>Number of people survived one year</em></u>
So, X ~ Binom(n = 12 , p = 0.20)
Now, the probability that 6 survived one year is given by = P(X = 6)
P(X = 6) =
=
= <u>0.0155</u>
