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Alex787 [66]
3 years ago
9

Tell me why NOBODY is helping me with my question I just posted Please Don’t answer them for points please The questions are on

my profile
Mathematics
1 answer:
Goryan [66]3 years ago
3 0

Answer:

I Could help :D

Step-by-step explanation:

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Solve 7x/9 -x= x/72 -5/8
suter [353]
Th answer is (45-17x)/72
5 0
4 years ago
PLEASE HELP WILL GIVE BRAINLIEST TO CORRECT ANSWER
olchik [2.2K]

ZX is √b²+a²

Step-by-step explanation:

From the diagram you notice that length WX is a and length WZ is b.ZX is the diagonal length formed by triangle ZWX.Apply the Pythagorean relationship here the sum of squares of the two sides equals the square of the diagonal.Hence;

ZW²+ WX²=ZX²

b²+a²=ZX²

√b²+a²=ZX

Learn More

Pythagorean relationship : brainly.com/question/11907296

Keyword : rectangle,diagonal length

#LearnwithBrainly

4 0
3 years ago
The probability that a student graduating from Suburban State University has student loans to pay off after graduation is . If t
xenn [34]

Answer:

Probability that the randomly selected two students both have no loans to pay = 0.09

Step-by-step explanation:

Probability that a student has a loan to pay is 0.7, hence probability that a student has no loan to pay is

1-0.7 = 0.3

Probability that the randomly selected two students both have no loans to pay = 0.3 × 0.3 = 0.09

3 0
4 years ago
Y = 3x + 3
Alchen [17]
First if x equals 1 then you would do 3x1 which would get you 3, then add the 3 plus 3 to get 6
7 0
3 years ago
X^2 - 2x + 1<br> x^2 - 2x - 1<br> x^2 + 2x + 1<br> In the denominator
mylen [45]

Answer:

x^{2} -4x+4 in the numerator

x^{2} -2x+1 in the denominator

Step-by-step explanation:

First fraction simplifies to:

\frac{x^{2}+x-6}{x^{2}-6x+5}\\\frac{x^{2}-2x+3x-6}{x^{2}-x-5x+5}\\\frac{x(x-2)+3(x-2)}{x(x-1)+5(x-1)}\\\frac{(x+3)(x-2)}{(x-1)(x+5)}\\

Dividing my a fraction is the same as multiplying by the reciprocal, so the second fraction simplifies to:

\frac{x^{2}-7x+10}{x^{2}+2x-3}\\\frac{x^{2}-2x+5x-10}{x^{2}-x+3x-3}\\\frac{x(x-2)+5(x-2)}{x(x-1)+3(x-1)}\\\frac{(x+5)(x-2)}{(x-1)(x+3)}\\

So the equation becomes:

\frac{(x+3)(x-2)}{(x+5)(x-1)} * \frac{(x+5)(x-2)}{(x-1)(x+3)}\\

The (x+3) and (x+5) terms cancel out, so what your left with is

\frac{(x-2)^{2}}{(x-1)^{2}}

Expanding this term you get the answer:

x^{2} -4x+4 in the numerator

x^{2} -2x+1 in the denominator

6 0
3 years ago
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