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2 years ago

What is the acceleration of a 10 kg block that experiences a 50 N applied force as it slides across a

Physics

1 answer:

Y_Kistochka [10]2 years ago

8 0

Hey can you send me a picture of your schedule and I will be in

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If you are stopped, then get on a bike and accelerate 2 m/s/s south, what us your final velocity after 3 seconds? Please Explain

olga_2 [115]

Vf = Final velocity.
Vi = initial velocity
a = acceleration.
t = time

Vf = Vi + at

Vf = 0 + (2 m/s^2)(3s)

Vf = 6 m/s south

4 0

3 years ago

Circle O has a circumference of approximately 44 in. Circle O with diameter d is shown. What is the approximate length of the di

GrogVix [38]

Answer:

14.001 in

Explanation:

Circumference = pi * diameter

Circumference / pi = diameter

44 inches/pi = 14.001 inches

5 0

3 years ago

Read 2 more answers

Air with a mass flow rate of 2.3 kg/s enters a horizontal nozzle operating at steady state at 450K, 350kPa, and a velocity of 3

MissTica

Answer:

(a) $A_1=0.283m^2$

(b) $Q=-105.5kW$ : From the air to the surroundings.

Explanation:

Hello,

(a) In this case, we can compute the area at the entrance by firstly computing the inlet volumetric flow:

$V_1=\frac{mRT_1}{P_1M}= \frac{2.3\frac{kg}{s} *8.314\frac{kPa*m^3}{kmol* K}*450K}{350kPa*28.97\frac{kg}{kmol} } =0.849\frac{m^3}{s}$

Then, with the velocity, we compute the area:

$A_1=\frac{V_1}{v_1}=\frac{0.849\frac{m^3}{s} }{3\frac{m}{s} } =0.283m^2$

(b) In this case, via the following energy balance for the nozzle:

$Q-W=H_2-H_1+\frac{1}{2} mV_2^2-\frac{1}{2} mV_1^2$

We can easily compute the change in the enthalpy by using the given Cp and neglecting the work (no done work):

$\Delta H=H_2-H_1=mCp\Delta T=2.3kg/s*1.011\frac{kJ}{kg*K}*(300K-450K)\\ \\\Delta H=-348.795kW$

Finally, the heat turns out:

$Q=-348.795kW+\frac{1}{2}*2.3\frac{kg}{s}*[(460\frac{m}{s})^2 -(3\frac{m}{s})^2 ]\\\\Q=-348.795kW+243329.65W*\frac{1kW}{1000W}\\ \\Q=-105.5kW$

Such sign, means the heat is being transferred from the air to the surroundings.

Regards.

4 0

3 years ago

A 4kg ball that is moving straight upward has 20J of kinetic energy and its total mechanical energy is 32J. Find the gravitation

Dovator [93]

Answer:

h = 0.25 [m]v = 3.26 [m/s]

Explanation: In order to solve this problem, we must remember that mechanical energy is defined as the sum of kinetic energy plus potential energy.

3 0

2 years ago

How does weight affect the time it takes an object to hit the ground?

ddd [48]

The heavier the object the faster it will fall. The lighter the object the slower to fall. You can test this for example with a rock and a piece of paper. The paper will take more time to for it to hit the ground rather than the rock which will be quicker.

7 0

3 years ago