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3 years ago

13

Physics question please show work for brainliest :)

2 answers:

kykrilka [37]3 years ago

7 0

The Impact of Physics on Society. Physics is the study of our natural world. From the microscopic level of particles to the macroscopic level of space, physics has changed our understanding of the universe and in doing so, has changed our philosophy and way of life.

navik [9.2K]3 years ago

5 0

A. A car comes equipped with side airbags. I don't know how I'm supposed to show work but that's the answer

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DESPERATE WILL GIVE BRAINLIST AND THANKS

Dafna11 [192]

Ethanol and biodoesel are also <u>cleaner-burning</u> fuels than pure gasoline and diesel fuel.

I hope I helped! :)

7 0

3 years ago

• What value is used to identify each element in the periodic table?

bearhunter [10]

Answer:

protons

Explanation:

5 0

3 years ago

An object 4 cm high is placed 20 cm in front of a convex lens of focal length 12 cm. What is the position and height of the imag

aleksandrvk [35]

It would be 12cm

hope this helps

6 0

3 years ago

If an object force of 50 N is used to move an object a distance of 20 m, what distance must the object be moved if the input for

steposvetlana [31]

Answer:

$\ d_{out} = 100 \ m.$

Explanation:

Given data:

$F_{in} = 50 \ \rm N$

$F_{out} = 10 \ \rm N$

$d_{in} = 20 \ m$

Let the distance traveled by the object in the second case be $d_{out}.$

In the given problem, work done by the forces are same in both the cases.

Thus,

$W_{in} = W_{out}$

$F_{in}.d_{in} = F_{out}.d_{out}$

$\Rightarrow \ d_{out} = \frac{F_{in}.d_{in}}{F_{out}}$

$\ d_{out} = \frac{50 \times 20}{10}$

$\ d_{out} = 100 \ m.$

5 0

3 years ago

In a double-slit experiment, light from two monochromatic light sources passes through the same double slit. The light from the

Dmitrij [34]

Answer:

$\lambda_2 = 573.3 nm$

Explanation:

As we know that the position of maximum intensity on the screen is given as

$y = \frac{N\lambda L}{d}$

here we know that

$\lambda$ = wavelength

L = distance of the screen

d = distance between two slits

now we know that the position of 8th maximum intensity is same as that of 9th maximum on the screen

so we have

$\frac{N_1\lambda_1 L}{d} = \frac{N_2 \lambda_2 L}{d}$

so here we have

$8 (645 nm) = 9 \lambda_2$

$\lambda_2 = 573.3 nm$

4 0

4 years ago