Given that,
Magnetic field strength is
B = 1.8T
The wedding ring has a diameter of
d = 2.23 cm = 0.023m
Time take t = 0.32 secs
A. Current induced
From ohms law
V= iR, given that R = 0.01Ω
So, we need to get the induced emf
Using
ε = -NdΦ / dt
Where Φ = BA
ε = -A ∆B / ∆t
ε = -¼πd²(B2-B1) / (t2-t1)
ε = -¼ × π × 0.023² × -1.8 / 0.32
ε = 0.0023371 V
Then
I = ε / R
I = 0.002337 / 0.01
I =0.2337 A
B. Power discippated?
Power is given as
P = iV
P = 0.2337 × 0.002337
P = 0.0005462 W
P = 0.56 mW
C. The magnetic field at the centre of the ring.
The electric field at the centre of the ring is zero because each part of the ring will cause a symmetrical opposite magnitude at every point,
Then, B = 0 T
The airplane engine uses oxygen from the air to keep the engines working. Rockets must carry their oxygen for the engines to operate. Third Law of Motion). Rocket propellants by combustion provide the hot gas es that produce reaction force (thrust) when ejected to the rear.
Wave energy is actually a concentrated form of solar power generated by the action of the wind blowing across the surface of the oceans water which can then be used as a renewable source of energy. As the suns rays strike the Earth's atmosphere, they warm it up.
Answer:
82.4 cm
Explanation:
∑F = ma
kx cos θ = ma
x = ma / (k cos θ)
x = (10 kg) (5 m/s²) / (70 N/m cos 30.0°)
x = 0.824 m
x = 82.4 cm
Answer:
The weight of the block on the moon is 15 kg.
Explanation:
It is given that,
The acceleration of the block, a = 7.5 m/s²
Force applied to the box, F = 70 N
The mass of the block will be, 

m = 9.34 kg
The block and table are set up on the moon. The acceleration due to gravity at the surface of the moon is 1.62 m/s². The mass of the object remains the same. It weight W is given by :


W = 15.13 N
or
W = 15 N
So, the weight of the block on the moon is 15 kg. Hence, this is the required solution.