Answer:
10) 9x - 2° = 5x + 54° (corresponding angles are equal)
9x - 5x = 54 + 2
4x = 56
x = 56/4
x = 14°
10y + 6° = 9x - 2° (linear pair)
10y + 6° = 9(14)° - 2°
10y + 6° = 126° - 2°
10y + 6° = 124°
10y = 124° - 6°
10y = 118
y = 118/10
Sorry, i don't know how to do the 11th question
but hope this helps you!
48
1st seat 6 possible for each 6 only 1 possible(spouse) for seat 2
3rd seat 4 possible for each 4 only 1 possible(spouse) for seat 4
5th seat 2 possible for each 2 only 1 possible(spouse) for seat 6
6 x 4 x 2 = 48
OR 3 couples possible arrangements 3 x 2 x1 = 6
each couple 2 possible 2 x 2 x 2 = 8
therefore 6 x 8 = 48
(6x–1)(6x+1) - 4x(9x+2) = −1
Simplify the left side:
36x^2-1 -36x^2-8x = -1
Combine like terms:
-1 -8x = -1
Add 1 to both sides:
-8x = 0
Divide both sides by -8:
x = 0 / -8
x = 0
The root is 0
Answer:
<h2>There is 8% probability of Kitzen winning first and Ava second.</h2>
Step-by-step explanation:
The given table shows that there are 4 students, so there are 4 possible winner in total, but they have different number of tickets.
The total number of tickets is 48, that's the total possible outcomes. Kitzen has a probability of

Ava has a probability of

Now, the probability of having one event and the other is

Therefore, there is 8% probability of Kitzen winning first and Ava second.
(Notice that the probaility is not about Kitzen or Ava winning, it's about winning both, that's why the percentage is low)