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Andreyy89
3 years ago
6

Which of the following is an example of balanced forces?

Physics
2 answers:
Sergio [31]3 years ago
6 0

A seesaw remains stationary when two students of equal weight sit on the ends

c

Leya [2.2K]3 years ago
5 0

Answer:

the answer is c.

Explanation:

a balanced force is a constant motion, or when the object does not move. because the children have the same weight, they can manage the seesaw to stay still.

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What is science?
vesna_86 [32]

Answer:

<h2>I don't know the answer but I have explanation </h2>

Explanation:

<h3>Science is further treated in a number of articles. For the history of Western and Eastern science, see science, history of. For the conceptualization of science and its interrelationships with culture, see science, philosophy of. For the basic aspects of the scientific approach, see physical science, principles of; and scientific method.Science can be divided into different branches based on the subject of study. The physical sciences study the inorganic world and comprise the fields of astronomy, physics, chemistry, and the Earth sciences. The biological sciences such as biology and medicine study the organic world of life and its processes. Social sciences like anthropology and economics study the social and cultural aspects of human behaviour.Science, any system of knowledge that is concerned with the physical world and its phenomena and that entails unbiased observations and systematic experimentation. In general, a science involves a pursuit of knowledge covering general truths or the operations of fundamental laws.</h3>

4 0
3 years ago
Read 2 more answers
By what factor must we increase the amplitude of vibration of an object at the end of a spring in order to double its maximum sp
strojnjashka [21]

Answer:

A'=2A

Explanation:

According to the law of conservation of energy, the total energy of the system can be expresed as the sum of the potential energy and kinetic energy:

E=U+K=\frac{kA^2}{2}\\E=\frac{kx^2}{2}+\frac{mv^2}{2}=\frac{kA^2}{2}

When the spring is in its equilibrium position, that is x=0, the object speed its maximum. So, we have:

\frac{k(0)^2}{2}+\frac{mv_{max}^2}{2}=\frac{kA^2}{2}\\A^2=\frac{mv_{max}^2}{k}\\A=\sqrt{\frac{mv_{max}^2}{k}}

In order to double its maximum speed, that is v'{max}=2v_{max}. We have:

A'=\sqrt{\frac{m(v'_{max})^2}{k}}\\A'=\sqrt{\frac{m(2v_{max})^2}{k}}\\A'=\sqrt{\frac{4mv_{max}^2}{k}}\\A'=2\sqrt{\frac{mv_{max}^2}{k}}\\A'=2A

6 0
3 years ago
Which option identifies the best technique to employ in the following scenario?
ollegr [7]
Answer: Urban Green House
8 0
2 years ago
I have a question regarding friction in rolling without slipping.
Solnce55 [7]

Explanation:

They probably put "rolls without slipping" in there to indicate that there is no loss in friction; or that the friction is constant throughout the movement of the disk. So it's more of a contingency part of the explanation of the problem.

(Remember how earlier on in Physics lessons, we see "ignore friction" written into problems; it just removes the "What about [ ]?" question for anyone who might ask.)

In this case, you can't ignore friction because the disk wouldn't roll without it.

As far as friction producing a torque... I would say that friction is a result of the torque in this case. And because the point of contact is, presumably, the ground, the friction is tangential to the disk. Meaning the friction is linear and has no angular component.

(You could probably argue that by Newton's 3rd Law there should be some opposing torque, but I think that's outside of the scope of this problem.)

Hopefully this helps clear up the misunderstanding for you.

4 0
3 years ago
The distance between Earth and Mars is 225 million km. When converted using the conversion factor 1 AU = 1.5 × 108 km, the dista
noname [10]
To convert km to AU, we divide 225,000,000 km by the factor of 1.5 x 10^8 = 150,000,000 km. This gives us 225,000,000 / 150,000,000 = 1.5 AU. Therefore, the distance between Earth and Mars in AU is 1.5 AU.
The AU is not equivalent to a light-year. A light-year is equivalent to around 9.5 x 10^12 kilometers.

4 0
4 years ago
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