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Andreyy89
3 years ago
6

Which of the following is an example of balanced forces?

Physics
2 answers:
Sergio [31]3 years ago
6 0

A seesaw remains stationary when two students of equal weight sit on the ends

c

Leya [2.2K]3 years ago
5 0

Answer:

the answer is c.

Explanation:

a balanced force is a constant motion, or when the object does not move. because the children have the same weight, they can manage the seesaw to stay still.

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A 50kg girl is playing soccer. She runs towards the ball at a speed of 7 m/s. How much kinetic energy does she have as she runs
stepladder [879]
The calculation for kinetic energy is this

KE = 1/2mv^2

KE = 1/2(50)(7^2)

KE = 1/2(49•50)

KE = 1225 kgm^2/s^2.

Or simply 1225 J.

She possess this much energy when she runs.
3 0
4 years ago
Read 2 more answers
You and your little sister go to the park in cheetah started to go down the plastic slide. On her way down to euros out ouch! Wh
gulaghasi [49]
As you slide down the plastic slide, electrons move from the plastic to you. ... Touch another person or an object (anything that isn't negatively charged by extra electrons) and ZAP! The electrons move from you to the other object. You get a shock
7 0
3 years ago
Playing with a stress ball you squeeze it as
shutvik [7]

Answer:

it dies

Explanation:

MWUAHHAHAHHA

8 0
3 years ago
Q 28.7: A strip 1.2 mm wide is moving at a speed of 25 cm/s through a uniform magnetic field of 5.6 T. What is the maximum Hall
Zinaida [17]

Answer:the  maximum Hall voltage across the strip= 0.00168 V.

Explanation:

The Hall Voltage is calculated using

Vh= B x v x  w

Where

B is the magnitude of the magnetic field, 5.6 T

v is the speed/  velocity of the strip, = 25 cm/s  to m/s becomes 25/100=0.25m/s

and w is the width of the strip=  1.2 mm to meters becomes 1.2 mm /1000= 0.0012m

 Solving

Vh= 5.6T x 0.25m/s x 0.0012m

=0.00168T.m²/s

=0.00168Wb/s

=0.00168V

Therefore, the  maximum Hall voltage across the strip=0.00168V

3 0
3 years ago
If your chunk of gold weighed 1 N in which case would you have the largest mass of gold?
kotykmax [81]
Ah ha !  Very interesting question.
Thought-provoking, even.

You have something that weighs 1 Newton, and you want to know 
the situation in which the object would have the greatest mass.

          Weight = (mass) x (local gravity)

          Mass  =  (weight) / (local gravity)

          Mass  =  (1 Newton) / (local gravity)

"Local gravity" is the denominator of the fraction, so the fraction
has its greatest value when 'local gravity' is smallest.  This is the
clue that gives it away.

If somebody offers you 1 chunk of gold that weighs 1 Newton,
you say to him:

   "Fine !  Great !  Golly gee, that's sure generous of you.  
But before you start weighing the chunk to give me, I want you
to take your gold and your scale to Pluto, and weigh my chunk
there.   And if you don't mind, be quick about it."

The local acceleration of gravity on Pluto is  0.62 m/s² ,
but on Earth, it's 9.81 m/s.

So if he weighs 1 Newton of gold for you on Pluto, its mass will be
1.613 kilograms, and it'll weigh 15.82 Newtons here on Earth. 

That's almost 3.6 pounds of gold, worth over $57,000 !


It would be even better if you could convince him to weigh it on
Halley's Comet, or on any asteroid.  Wherever he's willing to go
that has the smallest gravity.  That's the place where the largest
mass weighs 1 Newton.

3 0
4 years ago
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