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ruslelena [56]
3 years ago
13

Describe how the gravitational force between 2 objects depends on the mass of the objects and the distance between them. your an

swer
Physics
1 answer:
ollegr [7]3 years ago
3 0
The strength of the gravitational force between two objects depends<span> on </span>two<span>factors, </span>mass<span> and </span>distance<span>. the </span>force<span> of gravity the </span>masses<span> exert on each other. If one of the </span>masses<span> is doubled, the </span>force<span> of gravity </span>between<span> the </span>objects<span> is doubled. increases, the </span>force<span> of gravity decreases</span>
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What is the salt formed in the second sample reaction?
Bingel [31]

Answer:

This powder is sodium chloride. In the second reaction (sulfuric acid with copper(II) oxide) the resulting solution was blue in colour. When this solution was heated a small amount of white powder was noted.

Explanation:

i saw it on quizlet

5 0
3 years ago
A string is attached to a vibrating machine that has a frequency of 120 Hz. The other end of the string is passed over a pulley
BabaBlast [244]

Answer:

Explanation:

Given that,

The frequency of vibration is 120Hz

The mass of object attached is 0.5kg.

We want to find the tension In the string

The tension in the string is the weight of the object, it is how much gravity is pulling the object to the centre of the earth

Using newton second law.

F_net = m•a_y

The body is not accelerating the y-direction, then, a_y = 0

F_net = 0

Force acting on the string is the weight of the object and the tension in the string

T - W = 0

T = W

Where weight is mass × gravity

W = mg

Then,

T = W = mg

T = mg = 0.5 × 9.81

T = 4.905 N

The tension in the string is 4.905 N

4 0
3 years ago
How does time relate to motion
docker41 [41]
As we move, time goes up. Think of it on a graph; as time increases on the x axis, motion can either stay the same, increase, or decrease.
5 0
2 years ago
The electric field strength E 0 is measured at a perpendicular distance R from an infinitely large, thin sheet that contains a u
Brilliant_brown [7]

Answer:

Electric Field Strength E₀ = E₀ = Constant

Explanation:

The Electric Filed Strength E₀ to an Infinite uniformly charge large sheet is constant how far is it i.e. it is independent of the distance away from the uniformly charge sheet.

Formula: E₀ = σ / 2 ε₀  

7 0
3 years ago
Each tire on a car has a radius of 0.330 m and is rotating with an angular speed of 11.7 revolutions/s. Find the linear speed v
Eduardwww [97]

Answer:

The linear speed of the car, v, is 24.26 m/s

Explanation:

Given;

radius of the car's tire, r = 0.330 m

angular speed of the car, ω = 11.7 revolutions/s

The angular speed of the car in radian per second:

\omega = 11.7 \ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} \\\\\omega = 73.523 \ rad/s

The linear speed of the car, v, is calculated as;

v = ωr

v = 73.523 rad/s  x  0.33 m

v = 24.26 m/s

Therefore, the linear speed of the car, v, is 24.26 m/s

7 0
3 years ago
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