Question

How many grams of O2 are formed from 13.34 moles of KClO3? Provide your final answer rounded to two decimal places.

Answer 1

Answer:

640.32 g

Explanation:

2KClO₃ → 2KCl + 3O₂

First we convert KClO₃ moles to O₂ moles, using the stoichiometric coefficients:

• 13.34 mol KClO₃ * $\frac{3molO_{2}}{2molKClO_{3}}$ = 20.01 mol O₂

Then we convert O₂ moles to grams, using its molar mass:

• 20.01 mol O₂ * 32 g/mol = 640.32 g

So 640.32 g of O₂ are formed from 13.34 moles of KClO₃.