6)
P of <span>Regular heptagon = 7a = 7 x 12 = 84
Area </span>of Regular heptagon = 1/2 P a
Area of Regular heptagon = 1/2 (84)(8)
Area of Regular heptagon = = 336
answer
B. 336
7)
P of Regular nonagon= 9a = 9 x 9 = 81
Area of Regular heptagon = 1/2 P a
Area of Regular heptagon = 1/2 (81)(16)
Area of Regular heptagon = = 648
answer
D. 648
Answer:
if im right its 13.09 miles since perimiter is just the total length of the outside lines.
Step-by-step explanation:
Answer:
-1
Step-by-step explanation:
ssdsdsdsd
6. One variable only so pretty straightforward.
length-x+4
width-x
x+x+4=80
2x=76
x=38
x+4=42
answer: length 42cm and width 38cm
7. Another money problem!
n-# of nickels
q-# of quarters
n=3+q
0.05n+0.25q=2.85
Substitution works like a charm!
0.05(3+q)+0.25q=2.85
0.15+0.05q+0.25q=2.85
0.3q=2.7
q=9
n=3+q
n=3+9
n=12
answer: 9 nickels and 12 quarters
8. One variable situation again.
Ann's money-2b+9
Betty's money-b
b+2b+9=60
3b=51
b=17
2b+9=43
answer: Ann has $43 and Betty has $17.
9. # of red m&m's-x+1
# of blue m&m's-x
x+1+x=13
x=6
x+1=7
answer: 6 blue and 7 red m&m's
10. a-number of adult tickets
s-number of student tickets
a+s=785 ----> a=785-s
5a+2s=3280
5(785-s)+2s=3280
-3s=-645
s=215
a+s=785
a+215=785
a=570
answer: 215 children tickets and 570 adult tickets
Answer:
C. (4 , –1)
Step-by-step explanation:
<h2>—Math</h2>
x + y = 3
y = x –5
...........
<h3>eliminate y</h3>
x + y = 3
–x + y = –5
__________–
2x = 8
x = 4
x + y = 3
4 + y = 3
y = 3 –4
y = –1