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Valentin [98]
3 years ago
8

In H2 (g) + I2 (g) = 2HI (g), the initial reactions H2 and I2 are each equal to 1 mol / L.

Chemistry
1 answer:
mezya [45]3 years ago
3 0

Answer:

sorry mateeeeee dont know the answerrrrrr

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A substance that has a pH = 7 is a/an
Len [333]
Neutral solution, hope this helps :)
3 0
2 years ago
1. A student tried to solve the following problem by selecting the tile as shown. What, if anything, did the student do wrong?
slega [8]

Answer:

B. The student chose the correct tile, but needs to flip the tile to make the units cancel

Explanation:

Based on the reaction:

2AgNO₃(aq) + Cu(s) → 2Ag(s) + Cu(NO₃)₂ (aq)

<em>2 moles of AgNO₃ react per mole of Cu producing 2 moles of Ag and 1 mole of Cu(NO₃)₂</em>

Thus, if you want to produce 6.75moles of Cu(NO₃)₂ you need:

6.75moles of Cu(NO_3)_2  \frac{2 mol AgNO_3 }{1 mol Cu(NO_3)_2} = 13.50 moles of AgNO₃ are needed

Thus, if you analize the tile shown by the student:

<em>B. The student chose the correct tile, but needs to flip the tile to make the units cancel</em>

6 0
3 years ago
Comparing weak acids and strong acids of equal concentrations which of the following statements is true The pH of the weak acid
Firlakuza [10]

Answer:

the true statement is... The pH of the weak acid will be higher than the pH of the strong acid

Explanation:

pH is a measured of the extent to which acids dissociate into ions when plced in aqueous solution.

Strong acid dissociate near-completely, and weak acids barely dissociate.

At equal concentrations, a strong acid will have a lower pH than a weak acid, since the strong one will donate more proton to the solution.

6 0
3 years ago
Enter the correct 4 digit code (no spaces)
Airida [17]
3618 is the numbers for the graph
3 0
3 years ago
What mass of sodium hydroxide is needed to neutralise 24.5kg of sulfuric acid <br> H2SO4 + N2 = 2NH3
sveticcg [70]

Answer:

23.92 g

Explanation:

Molar mass of H2SO4 = (2×1)+32+(16×4)= 2+32+48= 82g/mol

H2SO4 + 2NaOH ---> Na2SO4 + 2H2O

I mole of H2SO4 = 2 moles of NaOH

24.5/82 = 24.5/82 × 2

= 0.598 moles of NaOH will neutralize

Mass= mole× molar mass

Molar mass of NaOH= 23+16+1 = 40g/mol

Mass= 0.598 × 40 = 23.92g of NaOH

7 0
3 years ago
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