All categories

3 years ago

When dynamic equilibrium is achieved, the rate of the forward and backward reactions go to zero. (T&F)

Chemistry

1 answer:

ratelena [41]3 years ago

5 0

Answer:

1) False

2) there are equal amounts of rectants and products

Explanation:

1) When dynamic equilibrium is achieved. the rate of forward and backward reaction they are the same, that is to say, two opposite reactions occur at the same rate, keeping the concentrations constant over time. Different to say the rate of the ractions go to zero.

2) A chemical equilibium exists when what is produce in quantities is equal to what reacts.

So the correct answer is the literal (d).

You might be interested in

How many grams of CO would be required to generate 635 g CO2

vivado [14]

The amount of CO that would be required to generate 635 g of CO2 will be 404.14 g

<h3>Stoichiometric problem</h3>

First, let us get the equation of the reaction:

$2CO + O_2 -- > 2CO_2$

From the equation, we can see that the mole ratio of CO to that of CO2 is 1:1.

635 g of CO2 is to be generated.

Mole of 635 g CO2 = mass/molar mass = 635/44.01 = 14.43 moles

Thus, the equivalent mole of CO required will also be 14.43 moles.

Mass of 14.43 moles CO = moles x molar mass = 14.43 x 28.01 = 404.14 g

Hence, 404.14 g of CO will be required to produce 635 g of CO2

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

7 0

2 years ago

What is the formula for the compound iodine trichoride?

Neko [114]

Answer:

Cl 3 I

Explanation:

Molecular Weight. 233.36. Appearance. Red-orange to brown powder or chunks. Melting Point. 63 °C

4 0

2 years ago

As the elements of group 16 (VIA) are considered from top to bottom on the Periodic Table, the atomic radii

mina [271]

For group 16 elements, the atomic radii increases down the group as a shell of electron is added on each time.

4 0

3 years ago

A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.

BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

$\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\ &=185.59\text{ g/mol} \end{aligned}$

Dimensional Analysis:

$\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }$

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

8 0

3 years ago

When the forces acting on the object are balanced the object will?

Volgvan

Answer:

When two forces acting on an object are of similar size but acting in opposite directions, we say they are forces of balance. If the forces on an object are balanced (or if there are no forces acting on it), this is what happens: the object stays stationary

8 0

3 years ago