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bearhunter [10]

3 years ago

5

An example of a physical change is A) cooking an egg. B) folding paper into a frog. C) rusting iron in an old bicycle. D) reacti

ng baking soda and vinegar to make a volcano.

2 answers:

blondinia [14]3 years ago

8 0

The correct answer is B

Sidana [21]3 years ago

8 0

the answer is b/////

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Which of the following is NOT a chemical change?

nataly862011 [7]

Answer:

Melting butter

Explanation:

You can reverse the change of butter back to its original state but you can never reverse the rest back to there original state

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3 years ago

Post-Lab Questions

Svet_ta [14]

Answer:

1. not enough dye was added to the drink.

The wrong dye was added to the drink

the water in the drink is evaporating

2. Changing the compound changes the absorbance behavior.

3. Measure the absorbance for the same solution in different cuvette sizes and find the y-intercept.

Explanation:

When the beverage company adds dye to the drink, there should be standard quantity added to the drink so that the color of the drink remains constant. When too much dye is added to the drink, the color will get dark brown or black. When the color of drink get lighter than green this means dye is not added in required quantity.

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3 years ago

Describe how to determine the rate law for an<br> overall reaction that involves multiple steps.

Zarrin [17]

Answer:

The sum of each elementary step in a reaction mechanism must yield the overall reaction equation. From the rate law of the rate-determining step it must agree with the experimentally determined rate law. The rate-determining step is the slowest step in a reaction mechanism. Because it is the slowest, it determines the rate of the overall reaction.

Explanation:

5 0

3 years ago

To dissolve one substance in another, thus forming a solution, three things must occur: The forces holding solute particles toge

aniked [119]

To dissolve one substance, attractions between solute and solvent particles must be formed, steps involved are:

<h3><u>Formation of a solution:</u></h3>

A physical process, not a chemical one, takes place when a solute and a solvent combine to produce a solution.
In other words, by applying the right separation techniques, both the solute and the solvent may be recovered in chemically unaltered forms.
It is claimed that two substances are entirely miscible when they combine to create a single homogenous phase in all ratios. Water and ethanol mix well, much like different gas combinations do.
When two substances, like oil and water, are fundamentally insoluble in one another, they are said to be immiscible.
We have already talked about several examples of gaseous solutions, such as the atmosphere of Earth.

Thus, a system that has two or more compounds homogeneously (in a single phase) dissolved in it is called a solution. It is the homogenous mixture formed when a solute dissolves in a solvent.

To know more about solutions, refer to:

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4 0

2 years ago

A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The

V125BC [204]

Taking into account the definition of calorimetry, the specific heat of metal is 0.165 $\frac{cal}{gC}$ .

<h3>Definition of calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

Q is the heat exchanged by a body of mass m.
C is the specific heat substance.
ΔT is the temperature variation.

<h3>Specific heat capacity of the metal</h3>

In this case, you know:

For metal:

Mass of metal = 50 g
Initial temperature of metal= 45 °C
Final temperature of metal= 11.08 ºC
Specific heat of metal= ?

For water:

Mass of water = 250 g
Initial temperature of water= 10 ºC
Final temperature of water= 11.08 ºC
Specific heat of water = 1.035 $\frac{cal}{gC}$

Replacing in the expression to calculate heat exchanges:

For metal: Qmetal= Specific heat of metal× 50 g× (11.08 C - 45 C)

For water: Qwater= 1.035 $\frac{cal}{gC}$ × 250 g× (11.08 C - 10 C)

If two isolated bodies or systems exchange energy in the form of heat, the quantity received by one of them is equal to the quantity transferred by the other body. That is, the total energy exchanged remains constant, it is conserved.

Then, the heat that the gold gives up will be equal to the heat that the water receives. Therefore:

- Qmetal = + Qwater

- Specific heat of metal× 50 g× (11.08 C - 45 C)= 1.035 $\frac{cal}{gC}$ × 250 g× (11.08 C - 10 C)

Solving:

- Specific heat of metal× 50 g× (-33.92 C)= 1.035 $\frac{cal}{gC}$ × 250 g× 1.08 C

Specific heat of metal× 1696 g×C= 279.45 cal

Specific heat of metal= $\frac{279.45 cal}{1696 gC}$

<u><em>Specific heat of metal= 0.165 </em></u> $\frac{cal}{gC}$

Finally, the specific heat of metal is 0.165 $\frac{cal}{gC}$ .

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7 0

2 years ago