The answer is 21m because the motion is in one dimension with constant acceleration.
The initial velocity is 0, because it started from rest, the acceleration <span>ax</span> is <span>4.7<span>m<span>s2</span></span></span>, and the time t is <span>3.0s</span>
Plugging in our known values, we have
<span>Δx=<span>(0)</span><span>(3.0s)</span>+<span>12</span><span>(4.7<span>m<span>s2</span></span>)</span><span><span>(3.0s)</span>2</span>=<span>21<span>m</span></span></span>
Answer:
Adding heat makes the particles move faster so the particles have more kinetic energy when more thermal energy is added
Explanation:
Metamorphic rocks are formed by tremendous heat, great pressure, and chemical reactions. To change it into another type of metamorphic rock you have to reheat it and bury it deeper again beneath the Earth's surface.
Hope this helped! :)
Answer: option D. the ratio of the population of male deer is not constant.
Explanation:
The bar graph permits to compare the results for two different populations: male and female deer in a very easy visual way.
These features are remarkable:
- The polulation of male deer (blue bars) decrease from 1961 to 1971, then increase in the next 10 year, decrease in the next decade, and increase for the next two decades. So, its trend is erratic, with ups and downs.
This discards the option A, which states that the population of male deer increases each decade from 1961 to 2011.
- The population of female deer (purple or brown bars) decreases every decade.
This discards the option B. which states that when the polulation of male deer increases, the poluplation of female deer also increases.
- The populations never are equal, hence this discards the option C.
- Since, one popultion increases and decreases, while the other population only decreases, you conclude that the ratio of the population of male deer to female deer is not constant, which is the option D.
Answer:
150 km/hr²
Explanation:
The data for the motion of the train includes;
The train starts from rest, therefore, the initial velocity of the train, u = 0 km/hr
The speed of the train after 0.5 hours, v = 75 km/hr
The change in time during the motion of the train, Δt = 0.5 hours
The acceleration, 'a', is the rate of change of velocity with time;
Therefore, we have;
a = (75 km/hr - 0 km/hr)/(0.5 hr) = 150 km/hr²
a = 150 km/hr² = 150 km/hr² × 1,000 m/km × hr²/(3,600 s)² = 5/432 m/s²
The acceleration of the train, a = 150 km/hr² = 5/432 m/s².
