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GuDViN [60]
2 years ago
6

A 10 kg cart is rolling across a parking lot with a velocity of .5 m/s. What is its momentum?

Physics
1 answer:
-Dominant- [34]2 years ago
4 0

Hello!

\large\boxed{p = 5  \text{ } kgm/s}

Use the equation for momentum:

p = mv

Plug in the given mass and velocity into the equation:

p = 10 * 0.5

p = 5 kgm/ s

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Firecracker A is 300 m from you. Firecracker B is 600 m from you in the same direction. You see both explode at the same time. D
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Answer:

e see that the distances are different, the only way that the two beams of light approach simultaneously is that event 2 (farthest) occurs first than event 1

Explanation:

This is an ejercise in special relativity, where the speed of light is constant.

Let's carefully analyze the approach, we see the two events at the same time.

The closest event time is

       c = (x₁-300) / t

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The time for the other event is

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since they tell us that we see the events simultaneously, we can equalize

        (x₁ -300) / c = (x₂ -600) / c

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We see that the distances are different, the only way that the two beams of light approach simultaneously is that event 2 (farthest) occurs first than event 1

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You will now examine the relationship between the number of field lines through a surface and the tangle betwcen A and E) angle
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Answer:

a. cosθ b. E.A

Explanation:

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b. From above, we have established that our electric flux, Ф = EAcosθ. Since this is the expression for the dot product of two vectors E and A where E is the number of electric field lines passing through the surface and A is the area of the surface and θ the angle between them, we write the electric flux as Ф = E.A  

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