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Oksi-84 [34.3K]
2 years ago
12

A softball pitcher throws a softball to a catcher behind home plate. the softball is 3 feet above the ground when it leaves the

pitcher’s hand at a velocity of 50 feet per second. if the softball’s acceleration is –16 ft/s2, which quadratic equation models the situation correctly? h(t) = at2 vt h0 h(t) = 50t2 – 16t 3 h(t) = –16t2 50t 3 3 = –16t2 50t h0 3 = 50t2 – 16t h0
Physics
1 answer:
Bumek [7]2 years ago
6 0

The correct option is (B) h(t) = -16t2 + 50t + 3

An equation like this has the generic form h(t) = at2 + v0t + h0,

where; a is the gravitational constant,

v0 is the initial velocity, and

h0 is the initial height.

Given that the gravitational constant is -16.

The equation h(t) = -16t2 + 50t + 3 is given by the starting velocity of 50 and the initial height of 3.

Learn more about Projectile with the help of the given link:

brainly.com/question/11422992

#SPJ4

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A rock of mass 200 g is attached to a 0.75 m long string and swung in a vertical plane.
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Hello!

a) Assuming this is asking for the minimum speed for the rock to make the full circle, we must find the minimum speed necessary for the rock to continue moving in a circular path when it's at the top of the circle.

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\Sigma F = T - F_g\\\\F_c = T - F_g\\\\\frac{mv^2}{r} = T - mg

Rearranging for 'T":
T =   \frac{mv^2}{r} +  mg\\\\

Plugging in the appropriate values:
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