A) The ball on the small ball is far smaller than the force on the basketball.
B) The total momentum before and after the collision remains constant.
C) We know momentum is conserved so we do:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.1 x 5 + 0.6 x 0 = 0.1 x -4 + 0.6 x v₂
v₂ = 1.5 m/s
Answer:
1.1 Two poles: North and South Poles.
1.2 - Staple pin - Nail - Tip of my phone charger - Metal keys - Cloth Hanger
1.3 - Wooden bed cot - Plastic pen - Game pad - Wooden shelf - Paper - A T-shirt
1.4 Yes
1.5 No
Answer:
1.98 m/s
Explanation:
To solve this, we would be using the law of conservation of energy, i.e total initial energy is equal to total final energy.
E(i) = E(f)
mgh = ½Iw² + ½mv²
Recall, v = wr, thus, w = v/r
Also, I = ½mr²
I = 0.5 * 5 * 2²
I = 10 kgm²
Remember,
mgh = ½Iw² + ½mv²
Substituting w for v/r, we have
mgh = ½I(v/r)² + ½mv²
Now, putting the values in the equation, we have
5 * 9.8 * 0.3 = ½ * 10 * (v/2)² + ½ * 5 * v²
14.7 = 1.25 v² + 2.5 v²
14.7 = 3.75 v²
v² = 14.7/3.75
v² = 3.92
v = √3.92
v = 1.98 m/s
Thus, the speed is 1.98 m/s
Answer:
The gas pressure is: 1.55 atm.
Explanation:
We need to use the equation that relate the variables given at the exercise (pressure, temperature and volume) from the ideal gas law formula, when the mass is constant we can reduce the expretion 
to 
solving to P2 we get:
replace the values 
.
