Question

A softball pitcher throws a softball to a catcher behind home plate. the softball is 3 feet above the ground when it leaves the pitcher’s hand at a velocity of 50 feet per second. if the softball’s acceleration is –16 ft/s2, which quadratic equation models the situation correctly? h(t) = at2 vt h0 h(t) = 50t2 – 16t 3 h(t) = –16t2 50t 3 3 = –16t2 50t h0 3 = 50t2 – 16t h0

Answer 1

The correct option is (B) h(t) = -16t2 + 50t + 3

An equation like this has the generic form h(t) = at2 + v0t + h0,

where; a is the gravitational constant,

v0 is the initial velocity, and

h0 is the initial height.

Given that the gravitational constant is -16.

The equation h(t) = -16t2 + 50t + 3 is given by the starting velocity of 50 and the initial height of 3.

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