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Oksi-84 [34.3K]
1 year ago
12

A softball pitcher throws a softball to a catcher behind home plate. the softball is 3 feet above the ground when it leaves the

pitcher’s hand at a velocity of 50 feet per second. if the softball’s acceleration is –16 ft/s2, which quadratic equation models the situation correctly? h(t) = at2 vt h0 h(t) = 50t2 – 16t 3 h(t) = –16t2 50t 3 3 = –16t2 50t h0 3 = 50t2 – 16t h0
Physics
1 answer:
Bumek [7]1 year ago
6 0

The correct option is (B) h(t) = -16t2 + 50t + 3

An equation like this has the generic form h(t) = at2 + v0t + h0,

where; a is the gravitational constant,

v0 is the initial velocity, and

h0 is the initial height.

Given that the gravitational constant is -16.

The equation h(t) = -16t2 + 50t + 3 is given by the starting velocity of 50 and the initial height of 3.

Learn more about Projectile with the help of the given link:

brainly.com/question/11422992

#SPJ4

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Which two changes would decrease the electric force between two charged
ch4aika [34]

Answer:

it is b and e

Explanation:

<h2>if u look at the words twice you will notice that b and e are both saying the same meanings just in diff rent words way u need to look close on things like that and u will get passing grades </h2>
6 0
2 years ago
Current is directly proportional to resistance.<br> a. True<br> b. False
ikadub [295]

IF voltage remains constant, then current is
inversely proportional to resistance.

The correct response is "b).", signifying "false" as the choice.

4 0
3 years ago
A 100-watt lightbulb uses 1 kilowatt-hour of electrical
Harlamova29_29 [7]

Answer:

Energy = 0.25 kilowatt-hour

Explanation:

Given the following data;

Power = 25 Watts

Time = 10 hours

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

Power = \frac {Energy}{time}

To find the energy consumed;

Energy = power * time

Substituting into the formula, we have;

Energy = 25 * 10

Energy = 250 Watt-hour

To convert to kilowatt-hour, we would divide by 1000;

Energy = 250/1000

Energy = 0.25 kilowatt-hour

3 0
3 years ago
Calculate the magnitude of electric field strength at a point 3cm from an infinite line of charge of linear density 18 μC/cm sit
valina [46]
Answer:

The magnitude of the electric field strength = 7.2 x 10⁸ N/C

Explanation:

The linear density:

\begin{gathered} \lambda=18\mu C\text{ /cm} \\  \\ \lambda=\frac{18*10^{-6}C}{0.01m} \\  \\ \lambda=0.0018\text{ C/m} \end{gathered}

Point r = 3 cm = 3/100 m

r = 0.03 m

The electric field strength is calculated below

\begin{gathered} E=\frac{\lambda}{2\pi\epsilon_o\epsilon_rr} \\  \\ E=\frac{0.0018}{2\times3.14\times8.85\times10^{-12}\times1.5\times0.03} \\  \\ E=719709237.468\text{ N/C} \\  \\ E=7.2\times10^8\text{ N/C} \\  \end{gathered}

The magnitude of the electric field strength = 7.2 x 10⁸ N/C

8 0
1 year ago
A 50gk boy on a rough horizontal ground the coefficeint of static friction is 0.68
Soloha48 [4]

Given that,

Mass of a boy = 50 kg

The coefficient of static friction = 0.68

To find,

Let us assume we need to find the maximum static friction between the boy and the ground.

Solution,

The formula for the maximum static friction between the two objects is given by :

F=\mu N

Where

N is normal force

Substitute all the values,

F=0.68\times 50\times 10\\\\F=340\ N

Therefore, the maximum static friction between the boy and the ground is 340 N.

4 0
3 years ago
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