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Oksi-84 [34.3K]
2 years ago
12

A softball pitcher throws a softball to a catcher behind home plate. the softball is 3 feet above the ground when it leaves the

pitcher’s hand at a velocity of 50 feet per second. if the softball’s acceleration is –16 ft/s2, which quadratic equation models the situation correctly? h(t) = at2 vt h0 h(t) = 50t2 – 16t 3 h(t) = –16t2 50t 3 3 = –16t2 50t h0 3 = 50t2 – 16t h0
Physics
1 answer:
Bumek [7]2 years ago
6 0

The correct option is (B) h(t) = -16t2 + 50t + 3

An equation like this has the generic form h(t) = at2 + v0t + h0,

where; a is the gravitational constant,

v0 is the initial velocity, and

h0 is the initial height.

Given that the gravitational constant is -16.

The equation h(t) = -16t2 + 50t + 3 is given by the starting velocity of 50 and the initial height of 3.

Learn more about Projectile with the help of the given link:

brainly.com/question/11422992

#SPJ4

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Answer: The correct statements are:

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Solid state: In this state, the molecules are closely packed and cannot move freely from one place to another that means no space between them and the intermolecular force of attraction between the molecules are strong.

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This relationship can be expressed as

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