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Arturiano [62]
3 years ago
5

In the soap testing experiment, what is the purpose of adding some MgCl2 to the soap solution at the end?

Chemistry
1 answer:
lakkis [162]3 years ago
4 0

Explanation:

The water is hard due to the presence of ions of Mg²⁺. Now in hard water soaps are ineffective . Since in hard water Mg²⁺ ion forms precipitate , which concludes less number of soap molecules are present in the solution and less amount of  froth  which disables the cleansing property of the soap .

Now the experiment , the very last step is the hard water test where some amount of MgCl₂ is added ,

Now this magnesium salt act as a source of Mg²⁺ ion and now the soap action can be determined , whether it is able to form froth or not .

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DerKrebs [107]

An allylic carbocation is an example of a system that is:

  • delocalized
  • conjugated.

<h3>What is allylic carbocation?</h3>

An allylic carbocation is a resonance-stabilized carbocation with a formal charge of +1 on an allylic carbon in each of the two resonance forms.

Thus, it is correct to state that:

An allylic carbocation is an example of a system that is:

  • delocalized
  • conjugated.

Learn more about allylic carbocation:
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Full Question:

An allylic carbocation is an example of a(n) _______ system. (Select all that apply.)

- localized

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6 0
1 year ago
How many kilojoules of heat are released when 32.0 g of NaOH are dissolved in water? (The molar heat of solution of NaOH is –445
Katen [24]
The energy release when dissolving 1 mol of NaOH in water is 445.1 kJ
the mass of NaOH to be dissolved is 32.0 g
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the energy released whilst dissolving 1 mol of NaOH - 445.1 kJ
when dissolving 0.8 mol - the energy released is 445.1 kJ/mol x 0.8 mol
therefore heat released is - 356.08 kJ
answer is -356.08 kJ
6 0
3 years ago
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Aluminum has a density of 2.7 g/cm3, how much space in cm3 would 81 grams of aluminum occupy? Show steps to answering this equat
Evgesh-ka [11]

Answer:

30 cm³

Explanation:

Step 1: Given data

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Step 2: Calculate the volume occupied by aluminum

The density of aluminum is equal to its mass divided by its volume.

ρ = m/V

V = m/ρ

V = 81 g / 2.7 g/cm³

V = 30 cm³

4 0
3 years ago
If 1.00L of water is added to 3.00 L
Bezzdna [24]

Answer:

4.5M

Explanation:

Here is why:

6 0
3 years ago
Which subatomic particle has negligible mass and travels around outside the nucleus?
allsm [11]
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The subatomic particles that are inside the nucleus are protons and neutrons.

The answer to your question is electron. 
7 0
4 years ago
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