Answer:
0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Mean of 0.6 times a day
7 day week, so 
What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.
In which
So
0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.
To find the unit rate you do distance ÷ time
16 miles ÷ 2 hours = 18
To find the time you do distance ÷ unit rate
20 miles ÷ 18 = 1.1
To find the distance you do time • unit rate
3 hours • 18 = 54
2) 1.1, 54, 1.8, 90, 27
3) 48, 3, 30, 2, 1
Answer:
E= -4,5
F=3,-2
Step-by-step explanation:
i think that's correct sorry if not
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➷ 3x + 1 = 511
Subtract 1 from both sides:
3x = 510
Divide both sides by 3:
x = 170
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Answer:
1/7
Report if wrong :)
Step-by-step explanation:
Also, I plead the 5th
