There are no options, but I would assume that these sequences would be geometric: 16, -8, 4, -2, 1 -15, -18, -21.6, -25.92, -31.104, 625, 125, 25, 5, 1 can possibly be the correct ones.
Use the hypergeometric distribution.
M=number of Men=5
F=number of women=4
m=number of men elected=2
f=number ow women elected=2.
Assuming equal chance to get elected, then
P(2M,2F)=C(M,m)*C(F,f)/C(M+F,m+f)
=C(5,2)*C(4,2)/C(9,4)
=10*6/126
=10/21
Reference: Hypergeometric distribution.
Answer:
1/7
Step-by-step explanation:
Step-by-step explanation:
20%=cows 0.4(40%)=goat 40%=sheep
if 40%sheep=40 sheeps
20% cow=x
20%×40=40%×x
8=40%x
x=8/40%
x=20
..so there are 20 cows
sorry...not sure
