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3 years ago

Explain how carbon is cycled between the hydrosphere and geosphere. Use specific examples.

1 answer:

5 0

Carbon is found in the solid form in geosphere of our earth. Coal and oil are some of the examples of materials containing carbon in the geosphere. when the coal or oil is burnt, carbon dioxide is formed and released in atmosphere. This carbon dioxide is absorbed by the water of the hydrosphere with the help of algae and plankton. The water turns acidic in nature. This way carbon is transferred from geosphere to hydrosphere.

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n April 1974, Steve Prefontaine completed a 10 km race in a time of 27 min , 43.6 s . Suppose "Pre" was at the 7.57 km mark at a

True [87]

Answer:

$0.084\ m/s^2$

Explanation:

<u>Given:</u>

Length of the race = 10 km
Distance traveled by Steve in 25 min = 7.57 km
Time interval for the constant acceleration = 60 s
Initial velocity of Steve = 0 m/s

<u>Assume:</u>

u = initial velocity
v = final velocity
t = time interval
a = constant acceleration

Since the person has the instantaneous velocity at 25 min equivalent to the average velocity of the person during this time interval. So, let us find out the average velocity of the person till 25 min time interval.

$v_{avg} = \dfrac{7.57\ km}{25\ min}\\\Rightarrow v_{avg} = \dfrac{7.57\times 1000\ m}{25\times 60\ s}\\\Rightarrow v_{avg} = 5.047\ m/s$

Since the person moves with a constant acceleration for the first 60 s and then moves with a constant velocity after this instant. This means the final velocity of the person at the end of 60 s is 5.047 m/s.

$\therefore v = 5.047\ m/s\\u = 0\ m/s\\t = 60\ s\\$

Now using the equation of constant acceleration, we have

$v = u +at\\\Rightarrow a = \dfrac{v-u}{t}\\\Rightarrow a = \dfrac{5.047-0}{60}\\\Rightarrow a =0.084\ m/s^2$

Hence, the acceleration of Steve in the 60 s interval is $0.084\ m/s^2$ .

3 0

2 years ago

A soup company wants to manufacture a can in the shape of a right circular cylinder that will hold 500 cm^3 of liquid. The mater

Rom4ik [11]

The area of the top and bottom:
2πr²
Cost for top and bottom:
2πr² x 0.02
= 0.04πr²

Area for side:
2πrh
Cost for side:
2πrh x 0.01
= 0.02πrh

Total cost:
C = 0.04πr² + 0.02πrh

We know that the volume of the can is:
V = πr²h
h = 500/πr²

Substituting this into the cost equation to get a cost function of radius:
C(r) = 0.04πr² + 0.02πr(500/πr²)
C(r) = 0.04πr² + 10/r

Now, we differentiate with respect to r and equate to 0 to obtain the minimum value:

0 = 0.08πr - 10/r²
10/r² = 0.08πr
r³ = 125/π

r = 3.41 cm

4 0

2 years ago

If you are in a rear-wheel skid, you must release your brakes and turn your steering wheel __________

g100num [7]

I think the correct answer would be A. If you are in a rear-wheel skid, you must release your brakes and turn your steering wheel into the direction of the skid. A skid in vehicles is a situation wherein one or more wheels are slipping in relation to the road and affecting the whole handling of the vehicle. To do a rear wheel skid, you should be releasing the break with caution and move or steer the wheel into the direction you would want to move.

3 0

3 years ago

1.a machine gun fires a ball with an initial velocity of 600m/s with an elevation of 30° with respect to the ground neglecting a

Sedbober [7]

Answer:

See explanation

Explanation:

a) maximum height of a projectile = u sin^2θ/2g

H= 600 × (sin 30)^2/2 × 10

H= 7.5 m

b) Time of flight

t= 2u sinθ/g

t= 2 × 600 sin 30/10

t= 60 seconds

Range

R= u^2sin2θ/g

R= (600)^2 × sin2(30)/10

R= 31.2 m

3 0

2 years ago

Enzo investigated the effect of different types of fertilizers on the growth of bean plants. He hypothesized that fertilizer B w

Mama L [17]

Answer:

The answer is "In this information, Enzo will be confident that if any fertilizer is required only for plants".

Explanation:

The Beans plants were members of the group of legumes. Legume flowering plant under which the roots form nodules. These nodules require a specific bacterium called bacteria, which fix nitrogen. Its bacterium transforms nitrogen from the atmosphere into the soil's nitrate. Consequently, for some of its growth, beans do not require fertilizer.

4 0

3 years ago