Answer:

Explanation:
<u>Given:</u>
- Length of the race = 10 km
- Distance traveled by Steve in 25 min = 7.57 km
- Time interval for the constant acceleration = 60 s
- Initial velocity of Steve = 0 m/s
<u>Assume:</u>
- u = initial velocity
- v = final velocity
- t = time interval
- a = constant acceleration
Since the person has the instantaneous velocity at 25 min equivalent to the average velocity of the person during this time interval. So, let us find out the average velocity of the person till 25 min time interval.

Since the person moves with a constant acceleration for the first 60 s and then moves with a constant velocity after this instant. This means the final velocity of the person at the end of 60 s is 5.047 m/s.

Now using the equation of constant acceleration, we have

Hence, the acceleration of Steve in the 60 s interval is
.
The area of the top and bottom:
2πr²
Cost for top and bottom:
2πr² x 0.02
= 0.04πr²
Area for side:
2πrh
Cost for side:
2πrh x 0.01
= 0.02πrh
Total cost:
C = 0.04πr² + 0.02πrh
We know that the volume of the can is:
V = πr²h
h = 500/πr²
Substituting this into the cost equation to get a cost function of radius:
C(r) = 0.04πr² + 0.02πr(500/πr²)
C(r) = 0.04πr² + 10/r
Now, we differentiate with respect to r and equate to 0 to obtain the minimum value:
0 = 0.08πr - 10/r²
10/r² = 0.08πr
r³ = 125/π
r = 3.41 cm
I think the correct answer would be A. If you are in a rear-wheel skid, you must release your brakes and turn your steering wheel into the direction of the skid. A skid in vehicles is a situation wherein one or more wheels are slipping in relation to the road and affecting the whole handling of the vehicle. To do a rear wheel skid, you should be releasing the break with caution and move or steer the wheel into the direction you would want to move.
Answer:
See explanation
Explanation:
a) maximum height of a projectile = u sin^2θ/2g
H= 600 × (sin 30)^2/2 × 10
H= 7.5 m
b) Time of flight
t= 2u sinθ/g
t= 2 × 600 sin 30/10
t= 60 seconds
Range
R= u^2sin2θ/g
R= (600)^2 × sin2(30)/10
R= 31.2 m
Answer:
The answer is "In this information, Enzo will be confident that if any fertilizer is required only for plants".
Explanation:
The Beans plants were members of the group of legumes. Legume flowering plant under which the roots form nodules. These nodules require a specific bacterium called bacteria, which fix nitrogen. Its bacterium transforms nitrogen from the atmosphere into the soil's nitrate. Consequently, for some of its growth, beans do not require fertilizer.