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wariber [46]
4 years ago
11

1. Two charged objects have a repulsive force of 2 N. If the charge of one of the objects is doubled, then the new force will be

________N.
Physics
1 answer:
GrogVix [38]4 years ago
5 0

Answer:

4 N

Explanation:

Electrostatic force is directly related to the charge of each object hence when the charge is doubled in only one of the objects, the force also double. If it's doubles on both objects, the force becomes four times. In this case, it's doubled on one object hence 2*2= 4 N

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What are the two factors that determine the amount of gravitational force between two objects?
melisa1 [442]

Answer:

The mass of the objects

Distance between the objects

Explanation:

The two factors that determines the amount of gravitational force between two objects is the mass of the objects and the distance between them.

Gravitational force of attraction is directly proportional to the product of the masses of the two objects and inversely proportional to the square of the distance between them. This is the postulate of the newton's law of universal gravitation.

 Mathematically:

        F = \frac{Gm_{1}m_{2}  }{r^{2} }

m is the mass

r is the distance

G is the universal gravitation constant

6 0
3 years ago
What is the following atmospheric property associated with?
drek231 [11]

Answer:

Your answer should be B. Cooled air

Explanation:

7 0
3 years ago
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When resistance is decreased in a circuit, current will _________.
Mars2501 [29]
The answer is A. Increase

The formula is <span>Voltage = Resistance X Current

Lets say the voltage is 10 and the resistence is 5

10 = 5 x current
Current = 2

Now, lets decrease the resistence from 5 to 2

10 = 2 x Current
Current = 5

The current increases
</span>
8 0
3 years ago
How many moles of MgCl2 are there in 329 g of the compound?<br><br> Your Answer:
Nookie1986 [14]

Answer:3.46

Explanation:

mass=329

molar mass=71

no. of moles=329/71

=3.46

6 0
3 years ago
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A force in the +x-direction with magnitude F(x)=18.0N−(0.530N/m)x is applied to a 8.90 kg box that is sitting on the horizontal,
Lady_Fox [76]

Answer:

6.875 m/s

Explanation:

The force is variable which is given by

F(x) = 18 - 0.53 x

mass of the box, m = 8.9 kg

initially it is at rest at x = 0

Let the velocity is v after travelling a distance of 15 m.

According to the work energy theorem, the work done by all the forces is equal to the change in kinetic energy of the body.

Work done = change in kinetic energy

\int \overrightarrow{F}.d\overrightarrow{x}=\Delta  K.E

\int_{0}^{15} \left ( 18-0.53 x \right )dx=\frac{1}{2}\times m \left ( v^{2}-u^{2} \right )

\left ( 18x-0.265x^{2} \right )_{0}^{15}=\frac{1}{2}\times 8.9\times  \left ( v^{2}-0^{2} \right )

18 x 15 - 0.265 x 15 x 15 = 4.45 x v²

270 - 59.625 = 4.45 v²

v² = 47.275

v = 6.875 m/s

Thus, the final velocity of the box is 6.875 m/s.

4 0
3 years ago
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