In this problem we have the electric field intensity E:
E = 6.5 × 
newtons/coulomb
We have the magnitude of the load:
q = 6.4 × 
coulombs
We also have the distance d that the load moved in a direction parallel to the field 1.2 × 
meters.
We know that the electric potential energy (PE) is:
PE = qEd
So:
PE = (6.4 × 
)(6.5 × )(1.2 × )
PE = 5.0 x 
joules
None of the options shown is correct.
Answer:
Explanation:
We have to use the centripetal force equation
we need the radious so we have to isolate "r" and we get
replacing m=65 kg, v= 4.1 m/s and Fc=455N we get
The radius of the amusement park chamber is 2.4m
Btu/(lb-°F) J/(g-°C i mean this is the correct answer
Answer:
Usually when climbing, it's best to be in the small front ring and the largest back ring. If your cadence is about 100 rpm, then whatever gear you're in is fine. It depends on the road, but as long as your pedaling is at a level you're comfortable with, you're fine.
Explanation:
Google answer by the way.
