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wariber [46]
3 years ago
11

1. Two charged objects have a repulsive force of 2 N. If the charge of one of the objects is doubled, then the new force will be

________N.
Physics
1 answer:
GrogVix [38]3 years ago
5 0

Answer:

4 N

Explanation:

Electrostatic force is directly related to the charge of each object hence when the charge is doubled in only one of the objects, the force also double. If it's doubles on both objects, the force becomes four times. In this case, it's doubled on one object hence 2*2= 4 N

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Help ASAP thanks !!!
Ann [662]

Answer:

true

Explanation:

3 0
3 years ago
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elixir [45]

Answer:

Cannot see all the answer choices but, when pressure goes up, volume goes down. So your best bet is to choose the graph that has a downward slant.

Explanation:

3 0
3 years ago
I just need x isolated
mamaluj [8]

Answer:

x=\frac{-y+\sqrt{y^2+4rt} }{2r}

x=\frac{-y-\sqrt{y^2+4rt} }{2r}

Explanation:

rx+y=\frac{t}{x}\\\\x(rx+y)=(\frac{t}{x})x\\\\rx^2+yx=t\\\\rx^2+yx-t=t-t\\\\rx^2+yx-t=0

Solve using the quadratic formula.

x=\frac{-y+\sqrt{y^2+4rt} }{2r}

x=\frac{-y-\sqrt{y^2+4rt} }{2r}

7 0
3 years ago
Read 2 more answers
How large is the acceleration of a 25 kg mass with a net force of 75 N applied horizontally to it?
Sveta_85 [38]

Answer:

Explanation:

F = ma

a = F/m

a = 75/25

a = 3 m/s²

8 0
3 years ago
What is the displacement of the car between t=1s and t=4s
tensa zangetsu [6.8K]

Answer:

Option C. 30 m

Explanation:

From the graph given in the question above,

At t = 1 s,

The displacement of the car is 10 m

At t = 4 s

The displacement of the car is 40 m

Thus, we can simply calculate the displacement of the car between t = 1 and t = 4 by calculating the difference in the displacement at the various time. This is illustrated below:

Displacement at t = 1 s (d1) = 10 m

Displacement at t= 4 s (d2) = 40

Displacement between t = 1 and t = 4 (ΔD) =?

ΔD = d2 – d1

ΔD = 40 – 10

ΔD = 30 m.

Therefore, the displacement of the car between t = 1 and t = 4 is 30 m.

4 0
3 years ago
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