Answer:
p^3 / q^12
Step-by-step explanation:
p^6 q^4
------------------
p^3 q^16
We know a^b / a^c = a^(b-c)
First with variable p
p^6 / p ^3 = p^(6-3) = p^3
Then with variable q
q^4 / q^16 = q^(4-16) = q^-12 and a^-b = 1/ a^b = 1 /q^12
p^3 * 1/ q^12
p^3 / q^12
So all u have to do is just add $1.28 and $0.54
11
A diagonal connects a vertex to another vertex without being a side of the polygon. There are 14 vertices in a 14-gon. This leaves 13 vertices left to connect to (since we cannot connect the vertex to itself). However, two of these vertices will form the sides of the 14-gon. This leaves us with 11 possible diagonals we can draw.
What do we complete there is no picture
Answer:
Move the top side down 2 meters
