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3 years ago

What 3 points must an object possess to be considered a planet

1 answer:

4 0

1. It must be an object which independently orbits the Sun (this means moons can't be considered planets, since they orbit planets)
2. It must have enough mass that its own gravity pulls it into a spheroidal shape.
3. It must be large enough to "dominate" its orbit (i.e. its mass must be much larger than anything else which crosses its orbit).

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Accelerates uniformly at 2.0 ms2 for 10.0s. Calculate its final velocity

Crazy boy [7]

Answer:

The distance is

Explanation:

Apply the equation of motion

(

)

The initial velocity is

−

The acceleration is

−

Therefore, when

, we get

(

)

⋅

and when

(

)

⋅

Therefore,

The distance travelled in the fourth second is

(

)

−

(

)

−

4 0

2 years ago

A man has 887.5 J of kinetic energy while running with a velocity of 5 m/s. What is his mass?

monitta

Answer:

The mass of the man is 71 kg

Explanation:

Given;

kinetic energy of the man, K.E = 887.5 J

velocity of the man, v = 5 m/s

The mass of the man is calculated as follows;

K.E = ¹/₂mv²

where;

m is the mass of the man

2K.E = mv²

m = 2K.E / v²

m = (2 x 887.5) / (5)²

m = 71 kg

Therefore, the mass of the man is 71 kg

7 0

3 years ago

You set your stationary bike on a high 80-N friction-like resistive force and cycle for 30 min at a speed of 8.0 m/s . Your body

stellarik [79]

A) The change in internal chemical energy is $1.15\cdot 10^7 J$

B) The time needed is 1 minute

Explanation:

First of all, we start by calculating the power output of you and the bike, given by:

$P=Fv$

where

F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed

v = 8.0 m/s is the velocity

Substituting,

$P=(80)(8.0)=640 W$

The energy output is related to the power by the equation

$P=\frac{E}{t}$

where:

P = 640 W is the power output

E is the energy output

$t = 30 min \cdot 60 = 1800 s$ is the time elapsed

Solving for E,

$E=Pt=(640)(1800)=1.15\cdot 10^6 J$

Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by

$\Delta E = \frac{E}{0.10}=\frac{1.15\cdot 10^6}{0.10}=1.15\cdot 10^7 J$

From the previous part, we found that in a time of

t = 30 min

the amount of internal chemical energy converted is

$E=1.15\cdot 10^7 J$

Here we want to find the time t' needed to convert an amount of chemical energy of

$E'=3.8\cdot 10^5 J$

So we can setup the following proportion:

$\frac{t}{E}=\frac{t'}{E'}$

And solving for t',

$t'=\frac{E't}{E}=\frac{(3.8\cdot 10^5)(30)}{1.15\cdot 10^7}=1 min$

Learn more about power and energy:

brainly.com/question/7956557

#LearnwithBrainly

3 0

3 years ago

How do you find density of a regular solid?

Effectus [21]

Put the object or material on a scale to figure out its mass. 3. Divide the mass by the volume to figure out the density (p = m / v). You may also need to know how to calculate the volume of a solid so use the formula

3 0

3 years ago

If a lamp has a resistance of 50 ohms and is operated by a p.d. of 10V, find the current flowing through it

NemiM [27]

V=IR therefore I=V/R=10/50=0.2A therefore the current is 0.2 A

4 0

3 years ago