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3 years ago

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What 3 points must an object possess to be considered a planet

1 answer:

Vitek1552 [10]3 years ago

4 0

<span>1. It must be an object which independently orbits the Sun (this means moons can't be considered planets, since they orbit planets)
2. It must have enough mass that its own gravity pulls it into a spheroidal shape.
3. </span><span>It must be large enough to "dominate" its orbit (i.e. its mass must be much larger than anything else which crosses its orbit).</span>

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Let the resistance of an electrical component remain constant while the potential difference across the two ends of the componen

slamgirl [31]

Answer:

The current through it will also decrease to half of its former value because according to Ohm's law the current flowing through a resistor is directly proportional to the potential difference applied across its ends provided that the temperature and some other necessary conditions remain constant.

This is mathematically represented as follows;

$V=IR.........(1)$

The current is thus given as

$I=\frac{V}{R}..............(2)$

if R is constant and V is reduced to half, then we have the following;

$I=\frac{V/2}{R}$

Simplifying further we obtain

$I=\frac{V}{2R}...........(3)$

Equation (3) shows that the current I is also reduced to half.

8 0

3 years ago

Read 2 more answers

An elevator accelerates upward at 2.0 m/s?,

amm1812

Answer:

Force the floor exerts on the passenger is 833 N.

Explanation:

Weight of passenger ( $F_{g}$ ) = mg = 85 × 9.8 N = 833 N

Force the floor exerts on the passenger ( $F_{N}$ ) = ?

For the elevator with the speed as 2.0 m/s the net force is zero, it means that the force is balanced.

i.e. $F_{N}$ = - $F_{g}$ = -mg = 833 N

hence $F_{N}$ is 833 N

If the lift was not at a constant speed i.e. if it had acceleration ( $m/s^{2}$ ) then the case would be different.

4 0

3 years ago

Any person for the job he applied Force moment or torque

VLD [36.1K]

Answer:

i think torque is the answer not confirmed

7 0

3 years ago

Interactive Solution 28.5 illustrates one way to model this problem. A 7.11-kg object oscillates back and forth at the end of a

____ [38]

Explanation:

Given that,

Mass of the object, m = 7.11 kg

Spring constant of the spring, k = 61.6 N/m

Speed of the observer, $v=2.79\times 10^8\ m/s$

We need to find the time period of oscillation observed by the observed. The time period of oscillation is given by :

$t_o=2\pi \sqrt{\dfrac{m}{k}} \\\\t_o=2\pi \sqrt{\dfrac{7.11}{61.6}} \\\\t_o=2.13\ s$

Time period of oscillation measured by the observer is :

$t=\dfrac{t_o}{\sqrt{1-\dfrac{v^2}{c^2}} }\\\\t=\dfrac{2.13}{\sqrt{1-\dfrac{(2.79\times 10^8)^2}{(3\times 10^8)^2}} }\\\\t=5.79\ s$

So, the time period of oscillation measured by the observer is 5.79 seconds.

3 0

3 years ago

A -0.00325 C charge q1 is placed 5.62 m from a second charge q2. The first charge is repelled with a 48900 N force. What is the

blagie [28]

Answer: q2 = -0.05286

Explanation:

Given that

Charge q1 = - 0.00325C

Electric force F = 48900N

The electric field strength experienced by the charge will be force per unit charge. That is

E = F/q

Substitute F and q into the formula

E = 48900/0.00325

E = 15046153.85 N/C

The value of the repelled second charge will be achieved by using the formula

E = kq/d^2

Where the value of constant

k = 8.99×10^9Nm^2/C^2

d = 5.62m

Substitutes E, d and k into the formula

15046153.85 = 8.99×10^9q/5.62^2

15046153.85 = 284634186.5q

Make q the subject of formula

q2 = 15046153.85/ 28463416.5

q2 = 0.05286

Since they repelled each other, q2 will be negative. Therefore,

q2 = -0.05286

6 0

3 years ago