Answer:
50
Step-by-step explanation:
sides are = so angles are also = !
Let one no. be x , Then according to question other number will be 8x
Now 8x - x = 70
7x = 70
x=10
hence one no is 10 and other 80
First we need to find the areas of both rectangles.
And area of larger rectangle = 10*5=50 square units
Area of smaller rectangle = 7*3 = 21 square units
Area between the two rectangles, = 50-21=29 square units
And since, we have to find the probability that a point is choosen is not in the shaded rectangle that is the smaller rectangle, so it means we have to find the probability of the point is choosen in the area between the two rectangles . Therefore,
Required probability =
Therefore correct option is the second option .
<span>You forgot to tell us how much the tickets cost each.
So I just arbitrarily chose that the price of a student
ticket is $4 and the price of a non-student ticket is $6.
<span>Let the number of student tickets be x
Let the number of non-student tickets be y
Price Money
Type Number of from
of of EACH ALL
ticket tickets ticket tickets
-------------------------------------------
student x $4 $4x
non-student y $6 $6y
-------------------------------------------
TOTALS 48 ----- $220
The first equation comes from the second column.
x + y = 48
The second equation comes from the last column:
4x + 6y = 220
So we have this system of equations:
.
We solve by substitution. Solve the first equation for y:
x + y = 48
y = 48 - x
Substitute (48 - x) for y in 4x + 6y = 220
4x + 6(48 - x) = 220
4x + 288 - 6x = 220
-2x + 288 = 220
-2x = -68
x = 34 = the number of student tickets.
Substitute in y = 48 - x
y = 48 - (34)
y = 14 non-student tickets.
Checking: 34 student tickets brings in $136 and 14 non-students is $84
That's 48 tickets.
And indeed $136 + $84 = $220
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