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Leya [2.2K]
3 years ago
5

A car initially traveling at 15 m/s speeds up at a constant rate of 2.0 m/s2 for 3 seconds. The velocity of the car at the end o

f the 3 second interval is _________ m/s.
Physics
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

Vf = 21 m/s

Explanation:

Data:

  • Initial Velocity (Vo) = 15 m/s
  • Acceleration (a) = 2.0 m/s²
  • Time (t) = 3 s
  • Final Velocity (Vf) = ?

Use formula:

  • Vf = Vo + a * t

Replace:

  • Vf = 15 m/s + 2.0 m/s² * 3s

Multiply the acceleration with time:

  • Vf = 15 m/s + 6 m/s

Solve the sum:

  • Vf = 21 m/s

The velocity of the car at the end of the 3 second interval is <u>21 meters per second.</u>

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