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nexus9112 [7]
3 years ago
14

NEED HELP ASAP! DUE NOW!!

Physics
1 answer:
docker41 [41]3 years ago
4 0
Oh okay the first person who answered is incorrect but


0—> PE=0J

1—>PE=1J

20—>PE=20J

50—>PE=50J

100—>PE=100J
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A light spring stretches 0.13 m when a 0.35 kg mass is hung from it. The mass is pulled down from this equilibrium position an a
Alenkasestr [34]

Answer:

v = 1.30 m/s

Explanation:

given,

mass hung = 0.35 Kg

spring stretched when load is hanged  (x)= 0.13 m

now,

weight of the mass attached = Kx

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6 0
3 years ago
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hodyreva [135]

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3 years ago
What is the only thing that can change
krok68 [10]

Answer:

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8 0
2 years ago
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W=- \frac{1}{2}kx_f^2
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tigry1 [53]

Answer:

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