Wow ! I understand your shock. I shook and vibrated a little
when I looked at this one too.
The reason for our shock is all the extra junk in the question,
put there just to shock and distract us.
"Neutron star", "5.5 solar masses", "condensed burned-out star".
That's all very picturesque, and it excites cosmic fantasies in
out brains when we read it, but it's just malicious decoration.
It only gets in the way, and doesn't help a bit.
The real question is:
What is the acceleration of gravity 2000 m from
the center of a mass of 1.1 x 10³¹ kg ?
Acceleration of gravity is
G · M / R²
= (6.67 x 10⁻¹¹ N·m²/kg²) · (1.1 x 10³¹ kg) / (2000 m)²
= (6.67 x 10⁻¹¹ · 1.1 x 10³¹ / 4 x 10⁶) (N) · m² · kg / kg² · m²
= 1.83 x 10¹⁴ (kg · m / s²) · m² · kg / kg² · m²
= 1.83 x 10¹⁴ m / s²
That's about 1.87 x 10¹³ times the acceleration of gravity on
Earth's surface.
In other words, if I were standing on the surface of that neutron star,
I would weigh 1.82 x 10¹² tons, give or take.
Answer:
1.7N
Explanation:
Force = kx
Where x = spring compression and
K = spring constant
K =85N/m
x = 2.0cm / 100
= 0.02m
Force = 85 x 0.02
= 1.7N
Gradpoint ? And the answer is water.
Answer:
Pemain A
Explanation:
Mengingat data berikut;
Kecepatan pemain A = 12 m/s
Kecepatan pemain B = 36 km/h
Untuk menentukan siapa pelari tercepat di antara dua pemain;
Pertama-tama, kita harus mengubah kecepatan menjadi satuan standar pengukuran yang sama.
Jadi, mari kita gunakan pengukuran umum meter per detik.
Konversi:
36 km/h = (36 * 1000)/(60 * 60)
36 km/h = 36000/3600
36 km/h = 10 m/s
Kecepatan pemain B = 10 m/s
Oleh karena itu, dibandingkan dengan kecepatan pemain A; pemain A lebih cepat.
Answer:
0.0109 m ≈ 10.9 mm
Explanation:
proton speed = 1 * 10^6 m/s
radius in which the proton moves = 20 m
<u>determine the radius of the circle in which an electron would move </u>
we will apply the formula for calculating the centripetal force for both proton and electron ( Lorentz force formula)
For proton :
Mp*V^2 / rp = qp *VB ∴ rp = Mp*V / qP*B ---------- ( 1 )
For electron:
re = Me*V/ qE * B -------- ( 2 )
Next: take the ratio of equations 1 and 2
re / rp = Me / Mp ( note: qE = qP = 1.6 * 10^-19 C )
∴ re ( radius of the electron orbit )
= ( Me / Mp ) rp
= ( 9.1 * 10^-31 / 1.67 * 10^-27 ) 20
= ( 5.45 * 10^-4 ) * 20
= 0.0109 m ≈ 10.9 mm
