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Olegator [25]
3 years ago
13

To increase the acceleration on the new station due to Earth's gravity, you decide

Physics
1 answer:
____ [38]3 years ago
6 0

To increase the acceleration due to gravity, we will place the new station in a shorter radius which is 1.2 RE.

<h3>What is acceleration due to gravity?</h3>
  • This is free fall of an object under the influence of gravitational pull.

The acceleration due to gravity of the new station due to Earth's gravity is calculated as follows;

g = \frac{GM}{R^2}

where;

  • g is the acceleration due to gravity
  • G is gravitational constant
  • M is the mass of the earth
  • R is the radius of the earth

To increase the acceleration due to gravity, the radius of the earth must be decreased. Thus, we will place the new station in a shorter radius which is 1.2 RE.

Learn more about acceleration due to gravity here: brainly.com/question/88039

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Explain how a form of<br> energy is used in daily life
hram777 [196]

Answer:

When we talk about residential uses of energy, these are the most basic uses of energy . They include watching television, washing clothes, heating and lighting at home , taking a shower, working from home on your laptop or computer, running appliances and cooking.

3 0
3 years ago
1. A soccer player kicks a soccer ball towards the goal. If she kicks it with a velocity of 24 m/s at an angle of 31 degrees abo
ruslelena [56]

Answer:

<em>The ball will go as high as 8.46 m</em>

Explanation:

<u>Projectile Motion</u>

It's the type of motion that experiences an object launched at a certain height above the ground and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g the acceleration of gravity, then the maximum height hm can be calculated as follows:

\displaystyle h_m=\frac{v_o^2\cdot \sin^2\theta}{2g}

The soccer ball is kicked at a speed of vo=24 m/s at an angle of θ=31°. Taking the value of g=9.8 m/s^2, then:

\displaystyle h_m=\frac{24^2\cdot \sin^2 31^\circ}{2\cdot 9.8}

\displaystyle h_m=\frac{576\cdot 0.2653}{19.6}

h_m=7.80~m

The ball will go as high as 8.46 m

4 0
3 years ago
Problem 5 You are playing a game where you drop a coin into a water tank and try to land it on a target. You often find this gam
Dvinal [7]

Answer:

Option D: 1.5in in front of the target

Explanation:

The object distance is y= 6in.

Because the surface is flat, the radius of curvature is infinity .

The incident index is n_i=\frac{4}{3} and the transmitted index is n_t= 1.

The single interface equation is \frac{n_i}{y}+\frac{n_t}{y^i}=\frac{n_t-n_i}{r}

Substituting the quantities given in the problem,

\frac{\frac{4}{3}}{6in}+\frac{1}{y^i}= 0

The image distance is then y^i=-\frac{18}{4}in =-4.5in

Therefore, the coin falls 1.5in in front of the target

6 0
3 years ago
Tick (3) the correct statement about electrostatic charges.
Radda [10]

Answer:

similar type of electric charges attract one another

I think this is a coorect staement

6 0
3 years ago
Read 2 more answers
They occupy the space surrounding the nucleus of the atom, they have a -1 charge
kipiarov [429]

Answer:

Electrons.

Explanation:

Look it up.

4 0
3 years ago
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