What is the speed of a wave with a wavelength of 3 m and a frequency of .1Hz?

2 answers:

6 0

We know,
Speed = Frequency * Wavelength
Speed = 3 * 0.1 m/s [hertz = 1/sec.]
So, your final answer is 0.3 m/s

Hope this helps!!

Akimi4 [234]3 years ago

6 0

The correct answer to the question is 0.3 m/s i.e the speed of the wave is 0.3 m/s.

CALCULATION:

As per the question, the wavelength of the wave is given as $\lambda=\ 3\ m.$

The frequency of the wave f = 0.1 Hz.

We are asked to calculate the speed [ V ] of the wave .

The relation among speed, frequency and wavelength of a wave is given as -

speed = frequency × wavelength

⇒ V = f × $\lambda$

= 3m × 0.1 Hz

= 0.3 m/s. [ans]

Hence, the speed of the wave will be 0.3 m/s.

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Racing cars driven by chris and kelly are side by side at the start of a race. the table shows the velocities of each car (in mi

Mamont248 [21]

Solution

distance travelled by Chris

\Delta t=\frac{1}{3600}hr.

X_{c}= [(\frac{21+0}{2})+(\frac{33+21}{2})+(\frac{55+47}{2})+(\frac{63+55}{2})+(\frac{70+63}{2})+(\frac{76+70}{2})+(\frac{82+76}{2})+(\frac{87+82}{2})+(\frac{91+87}{2})]\times\frac{1}{3600}

=\frac{579.5}{3600}=0.161miles

Kelly,

\Delta t=\frac{1}{3600}hr.

X_{k}=[(\frac{24+0}{2})+(\frac{3+24}{2})+(\frac{55+39}{2})+(\frac{62+55}{2})+(\frac{71+62}{2})+(\frac{79+71}{2})+(\frac{85+79}{2})+(\frac{85+92}{2})+(\frac{99+92}{2})+(\frac{103+99}{2})]\times\frac{1}{3600}

=\frac{657.5}{3600}

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4 0

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