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3 years ago

Which may result from an increase in friction? Check all that apply.

Physics

1 answer:

Yuri [45]3 years ago

4 0

I am sure that the answer increased traction. :D

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A bowling ball is on the end of a rope of length 5 meters, the other end of which is attached to a hook in the ceiling. The ball

pogonyaev

Answer:

$a = 0\,\frac{m}{s^{2}}$

Explanation:

Let consider the following system, which is described in the image attached below and two reference axis, one parallel and the other perpendicular to the direction of motion. The corresponding equations of equilibrium are described herein:

$\Sigma F_{n} = T - m\cdot g \cdot \cos \theta = 0$

$\Sigma F_{t} = m\cdot g \cdot \sin \theta = m\cdot a$

The acceleration of the bowling ball at the lowest point occurs at $\theta = 0^{\textdegree}$

$m\cdot g \cdot \sin \theta = m\cdot a$

$g\cdot \sin \theta = a$

$a = 0\,\frac{m}{s^{2}}$

6 0

3 years ago

Define relative velocity with an example. A man is going

makkiz [27]

Answer:

4.24m/s,45 degrees in forward direction

Explanation:

6 0

2 years ago

Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. when they hit the ground

Setler79 [48]

They will both hit the ground at the same time because gravitational acceleration for all objects is the same.

6 0

3 years ago

A 1-kg collar (located at point (2,2) from the origin) is pulled along a vertical, frictionless bar with a force of 10 N applied

faltersainse [42]

Answer:

The acceleration of the collar is 10 m/s²

Explanation:

Given;

mass of the collar, m = 1 kg

applied force on the bar, F = 10 N

The acceleration of the collar can be calculated by applying Newton's second law of motion;

F = ma

where;

F is the applied force

m is mass of the object

a is the acceleration

a = F / m

a = 10 / 1

a = 10 m/s²

Therefore, the acceleration of the collar is 10 m/s²

3 0

2 years ago

Newly discovered planet has twice the mass and three times the radius of the earth. What is the free-fall acceleration at its su

skad [1K]

Answer:

$g_n=\dfrac{2}{9}g$

Explanation:

M = Mass of Earth

G = Gravitational constant

R = Radius of Earth

The acceleration due to gravity on Earth is

$g=\dfrac{GM}{R^2}$

On new planet

$g_n=\dfrac{G2M}{(3R)^2}\\\Rightarrow g_n=\dfrac{2GM}{9R^2}$

Dividing the two equations we get

$\dfrac{g_n}{g}=\dfrac{\dfrac{2GM}{9R^2}}{\dfrac{GM}{R^2}}\\\Rightarrow \dfrac{g_n}{g}=\dfrac{2}{9}\\\Rightarrow g_n=\dfrac{2}{9}g$

The acceleration due to gravity on the other planet is $g_n=\dfrac{2}{9}g$

4 0

2 years ago

Read 2 more answers