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3 years ago

Which may result from an increase in friction? Check all that apply.

Physics

1 answer:

Yuri [45]3 years ago

4 0

I am sure that the answer increased traction. :D

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A merry-go-round with a rotational inertia of 600 kg m2 and a radius of 3. 0 m is initially at rest. A 20 kg boy approaches the

Margaret [11]

Hi there!

$\boxed{\omega = 0.38 rad/sec}$

We can use the conservation of angular momentum to solve.

$\large\boxed{L_i = L_f}$

Recall the equation for angular momentum:

$L = I\omega$

We can begin by writing out the scenario as a conservation of angular momentum:

$I_m\omega_m + I_b\omega_b = \omega_f(I_m + I_b)$

$I_m$ = moment of inertia of the merry-go-round (kgm²)

$\omega_m$ = angular velocity of merry go round (rad/sec)

$\omega_f$ = final angular velocity of COMBINED objects (rad/sec)

$I_b$ = moment of inertia of boy (kgm²)

$\omega_b$ = angular velocity of the boy (rad/sec)

The only value not explicitly given is the moment of inertia of the boy.

Since he stands along the edge of the merry go round:

$I = MR^2$

We are given that he jumps on the merry-go-round at a speed of 5 m/s. Use the following relation:

$\omega = \frac{v}{r}$

$L_b = MR^2(\frac{v}{R}) = MRv$

Plug in the given values:

$L_b = (20)(3)(5) = 300 kgm^2/s$

Now, we must solve for the boy's moment of inertia:

$I = MR^2\\I = 20(3^2) = 180 kgm^2$

Use the above equation for conservation of momentum:

$600(0) + 300 = \omega_f(180 + 600)\\\\300 = 780\omega_f\\\\\omega = \boxed{0.38 rad/sec}$

8 0

3 years ago

Another athlete using a different spring exerts an average force of 400 N to enable her

babymother [125]

Answer:84Nm

Explanation:

force=400N

Distance=0.210m

Workdone=force x distance

Workdone=400 x 0.210

Workdone=84Nm

6 0

3 years ago

Label the following descriptions with (M) for Mass or (W) for Weight. ____measured with a spring scale ____measured in Newtons _

Valentin [98]

1. mass
2. weight
3. weight
4. weight
5. mass
6. mass

8 0

3 years ago

How long tg does it take for the balls to reach the ground? use 10 m/s2 for the magnitude of the acceleration due to gravity.

erik [133]

Answer:

1.0s

Explanation:

distance = 1/2 × acceleration × time2 + intial speed × time

5 0

3 years ago

What level of intensity is bicycling 5-9 mph on level terrain?

ruslelena [56]

The answer is moderate intensity

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3 years ago