Answer:
0.00899 N
Explanation:
The magnitude of the electrostatic force between two charges is given by the equation:
where:
is the Coulomb's constant
are the charges
r is the distance between the two charges
And the force is:
- Repulsive if the two charges have same sign
- Attractive if the two charges have opposite sign
In this problem we have:
(charge of object 1)
(charge of object 2)
r = 1 m (separation between the objects)
So, the electric force is
7. PE=0.5×700n/m×0.9m^2
0.9^2=0.81m
0.5×700×0.81= 283.5J
8. 2000=0.5×(x)×1.5m^2
1.5^2= 0.25
0.25×0.5=0.125
2000=0.125 (x)
2000/0.125=x
x=16000 n/m
9. 4000=0.5 (375 n/m)×(x)^2
0.5×187.5 (x)
4000/187.5=21.3333333333
Hi there!
We can use Newton's Second Law:
ΣF = Net force (N)
m = mass (kg)
a = acceleration (m/s²)
We can rearrange the equation to solve for the acceleration.
Before the skydiver opens the parachute, his velocity would be increasing greatly as much as 9.8 m/s². Opening the parachute would increase the surface area to which air may cause resistance. The skydiver then reaches his terminal velocity.
