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const2013 [10]
2 years ago
5

How many atoms are there in 0.028 grams of iron metal? 12:50 ✓

Chemistry
1 answer:
labwork [276]2 years ago
3 0

Answer:

30100000000000000000 atoms

Explanation:

Ar of Fe : 56

0.028/56 = 0.0005 moles of Fe

0.0005 * 6.02 * 10^23(Avagardro's law of constant)

= 3.01*10^20 atoms

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What is the unit of temperature on a solubility graph
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Answer:

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Explanation:

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6 0
2 years ago
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how can you tell if a compound is covalent or ionic from the formula, and how each is named differently?
kumpel [21]

Answer:

ionic compounds contain a metal and a non metal

covalent compounds contain only non metals

Explanation:

Each type of compound is named according to different rules.

5 0
3 years ago
. A container with a volume of 0.50 L contains air at a pressure of 1.0 atm. If the volume is reduced to 0.10 L at constant temp
marin [14]

Answer:

The answer to your question is Pressure = 5 atm

Explanation:

Data

Volume 1 = V1 = 0.5 l

Pressure 1 = P1 = 1 atm

Volume 2 = V2 = 0.1 l

Pressure 2 = P2 = x

Formula

To solve this problem use the Boyle's equation

                      V1P1 = V2P2

Solve for P2

                     P2 = V1P1/V2

Substitution

                     P2 = (0.5 x 1) / 0.1

Simplification

                     P2 = 0.5/0.1

Result

                     P2 = 5 atm          

3 0
3 years ago
Propane camping stoves produce heat by the combustion of gaseous propane (C3H8). Balance the skeletal equation for the combustio
Darina [25.2K]
Easy (: 

C₃H₈ (g) + O₂ (g) ---> CO₂ (g) + H₂O 

1 C₃H₈ (g) +  5 O₂ (g) ---> 3 CO₂ (g) + 4 H₂O 

With this there is the same amount of elements on each side (You take the larger number in front and multiply it by whats after it. So you have 3 C, 8 H, and 10 O on one side, and then the next mirrors is with 3 C, 8 H, and 10 O. 

3 0
2 years ago
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A ballon is inflated with 2.42L of helium at a temperature of 27.0°C. When put in the freezer, the volume changes to 2.37L and -
natita [175]

Answer:

838 torr  

Step-by-step explanation:

To solve this problem, we can use the <em>Combined Gas Laws</em>:

p₁V₁/T₁ = p₂V₂/T₂            Multiply each side by T₁

   p₁V₁ = p₂V₂ × T₁/T₂     Divide each side by V₁

      p₁ = p₂ × V₂/V₁ × T₁/T₂

<em>Data: </em>

p₁ = ?;             V₁ = 2.42 L; T₁ =  27.0 °C

p₂ = 754 torr; V₂ = 2.37 L; T₂ =  -8.8 °C

Calculations:

(a) Convert <em>temperatures to kelvins </em>

T₁ = (27.0 + 273.15) K = 300.15 K

T₂ = (-8.8 + 273.15) K = 264.35 K

(b) Calculate the<em> pressure </em>

p₁ = 754 torr × (2.37 L/2.42) × (300.15/264.35)  

p₁ = 754 torr × 0.979 × 1.135

p₁ = 838 torr

5 0
3 years ago
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