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3 years ago

Centripetal acceleration depends directly on the square of the object's speed and inversely on

Physics

1 answer:

11Alexandr11 [23.1K]3 years ago

8 0

Answer:

True.

Explanation:

The formula for the centripetal acceleration of an object can be calculated by the formula as follows :

$a_c=\dfrac{v^2}{r}$

Where

v is the speed of an object

r is the radius of the circle

It means, the centripetal acceleration depends directly on the square of the object's speed and inversely on the radius of the circle. Hence, the given statement is true.

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The table shows the commonly eaten foods of some groups of organisms.

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Explanation:

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4 years ago

A 148 g ball is dropped from a tree 11.0 m above the ground. With what speed would it hit the ground

forsale [732]

Answer:

14.68m/s

Explanation:

As per the question, the data provided is as follows

Mass = M = 0.148 kg

Height = h = 11 m

Initial velocity = U = 0 m/s

Final velocity = V

Gravitational force = F

Mass = M

Based on the above information, the speed that hit to the ground is

As we know that

Work to be done = Change in kinetic energy

$F ( S) = (\frac{1}{2} ) M ( V^2 - U^2 )$

$M g h = (\frac{1}{2} ) M ( V^2 - U^2 )$

$g h = (\frac{1}{2} ) ( V^2 - U^2 )$

$V^2 - U^2 = 2gh$

$V^2 - 0 = 2gh$

$V = \sqrt{2 g h}$

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= 14.68m/s

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3 years ago

What causes the different season on earth

viktelen [127]

The Short Answer: Earth’s tilted axis causes the seasons. Throughout the year, different parts of Earth receive the Sun’s most direct rays. So, when the North Pole tilts toward the Sun, it’s summer in the Northern Hemisphere. And when the South Pole tilts toward the Sun, it’s winter in the Northern Hemisphere.

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3 years ago

The planet Uranus has a radius of 25,360 km and a surface acceleration due to gravity of 9.0 m/s^2 at its poles. Its moon Mirand

AlexFokin [52]

Answer:

$8.67791\times 10^{25}\ kg$

$0.34589\ m/s^2$

$0.07903\ m/s^2$

Explanation:

M = Mass of Uranus

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Uranus = 25360 km

h = Altitude = 104000 km

$r_m$ = Radius of Miranda = 236 km

m = Mass of Miranda = $6.6\times 10^{19}\ kg$

Acceleration due to gravity is given by

$g=\dfrac{GM}{r^2}\\\Rightarrow M=\dfrac{gr^2}{G}\\\Rightarrow M=\dfrac{9\times 25360000^2}{6.67\times 10^{-11}}\\\Rightarrow M=8.67791\times 10^{25}\ kg$

The mass of Uranus is $8.67791\times 10^{25}\ kg$

Acceleration is given by

$a_m=\dfrac{GM}{(r+h)^2}\\\Rightarrow a_m=\dfrac{6.67\times 10^{-11}\times 8.67791\times 10^{25}}{(25360000+104000000)^2}\\\Rightarrow a_m=0.34589\ m/s^2$

Miranda's acceleration due to its orbital motion about Uranus is $0.34589\ m/s^2$

On Miranda

$g_m=\dfrac{Gm}{r_m^2}\\\Rightarrow g_m=\dfrac{6.67\times 10^{-11}\times 6.6\times 10^{19}}{236000^2}\\\Rightarrow g_m=0.07903\ m/s^2$

Acceleration due to Miranda's gravity at the surface of Miranda is $0.07903\ m/s^2$

No, both the objects will fall towards Uranus. Also, they are not stationary.

6 0

3 years ago