Answer:
a) (momentum of the elephant), p1 = 14625 kg×m/s
b) p1 = 609.4×p2
c) (momentum of the hunter), p3 = 720 kg×m/s.
Explanation:
a) if m = 1950 kg is the mass of the elephant and V = 7.50 m/s be the speed of the elephant, then the momentum is given by:
p1 = m×V = (1950)×(7.50) = 14625 kg×m/s
b) if m = 0.0400 kg is the mass of the bullet and v = 600 m/s be the speed of the bullet, then the momentum of the bullet is given by:
p2 = m×v = (0.0400)×(600) = 24 kg.m/s
then:
p1/p2 = (14625)/(24) = 609.4
that is, p1 = 609.4×p2
Therefore, the momentum of the elephant is 609.4 times the momentum of the bullet.
c) the momentum og the hunter after missing the elephant is given by:
p3 = m×v = (90.0)×(8) = 720 kg.m/s
Therefore, the momentum of the hunter is 720 kg×m/s.
Answer:
the initial velocity of the ball is 17.14 m/s
Explanation:
Given;
maximum height reached by the ball, h = 15 m
let the initial velocity of the ball = u
at maximum height, the final velocity of the ball is zero, v = 0
The initial velocity of the ball is calculated by using the following upward motion kinematic equation;
v² = u² - 2gh
0 = u² - 2(9.8 x 15)
u² = 294
u = √294
u = 17.14 m/s
Therefore, the initial velocity of the ball is 17.14 m/s
You use the right hand rule. With your thumb out and the rest of your fingers curved ( like a thumbs up) curve your fingers to the direction of the torque. The direction your thumbs points at is the direction of the torque
For this case we have that by definition, the momentum equation is given by:

Where:
m: It is the mass
v: It is the velocity
According to the data we have:

Substituting:

On the other hand, if we clear the variable "mass" we have:

According to the data we have:

Thus, the mass is 
Answer:

We can find the answer step-by-step:
1) The electric charges on a conductor must lie entirely on its surface. This is because the charges have same sign, so the force acting between each other is repulsive therefore the charges must be as far apart as possible, i.e. on the surface of the conductor.
2) We consider a cylinder perpendicular to the surface of the conductor, that crosses the surface with its section. We then apply Gauss law, which states that the flux of the electric field through this cylinder is equal to the total charge inside it divided the electrical permittivity:

3) The electric field outside the surface is perpendicular to the surface itself (otherwise there would be a component of the electric force parallel to the surface, which would move the charge, violating the condition of equilibrium). The electric field inside the conductor is instead zero, because otherwise charges would move violating again equilibrium condition. Therefore, the only flux is the one crossing the section A of the cylinder outside the surface:

4) The total charge contained in the cylinder is the product between the section, A, and the charge density

on the surface of the conductor:

5) Substituting the flux and the charge density inside Gauss law, we can find the electric field just outside the surface of the conductor:

therefore