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vovikov84 [41]
3 years ago
13

Which correctly describes the laws of conservation?

Chemistry
1 answer:
VashaNatasha [74]3 years ago
5 0

                                                       A is the answer

Venn diagrams are used for comparing and contrasting different topics. The overlapping sections show characteristics that the topics have in common, and the sections that are unique to each topic show the characteristics apply to only that topic.

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3CuCl2 + 2Al => 3Cu + 2AlCl3
Marrrta [24]

The reaction includes the single replacement reaction and redox

<h3>Further explanation</h3>

Single replacement : one element replaces another element in a compound

A + BC ⇒ AC + B

The oxidation-reduction reaction or abbreviated as Redox is a chemical reaction in which there is a change in oxidation number

3CuCl + 2Al => 3Cu + 2AlCl₃

  • 1. Single replacement

Al replacing Cu in the CuCl compound

  • 2. Redox reaction

3Cu²⁺ + 6e⁻⇒ 3Cu reduction(oxidation number from +2 to 0)

2Al⇒2Al³⁺+6e⁻ oxidation(oxidation number from 0 to +3)

8 0
3 years ago
Determine the oh of a solution that is 0.220 m in hco3
ICE Princess25 [194]

Answer : The hydroxide ion concentration of a solution is, 5\times 10^{-14}

Explanation :

As we know that HCO_3^- dissociates in water to give hydrogen ion (H^+) and carbonate ion (CO_3^{2-}).

As, 1 mole of HCO_3^- dissociates to give 1 mole of hydrogen ion (H^+)

Or, 1 M of HCO_3^- dissociates to give 1 M of hydrogen ion (H^+)

So, 0.200 M of HCO_3^- dissociates to give 0.200 M of hydrogen ion (H^+)

Now we have to calculate the hydroxide ion concentration.

As we know that:

[H^+][OH^-]=1\times 10^{-14}

0.200\times [OH^-]=1\times 10^{-14}

[OH^-]=5\times 10^{-14}

Therefore, the hydroxide ion concentration of a solution is, 5\times 10^{-14}

6 0
3 years ago
A student has two objects. Object 1 has a mass of 28 g and a volume of 12 cubic
bearhunter [10]

Answer:

Object 2 with a density of 0.68

Explanation:

object 2 has a lower density than water so it will float

8 0
2 years ago
What is the percent by mass of water in Na S04.10H20?
dalvyx [7]

Answer:

                    Percent by mass of water is 56%

Explanation:

                    First of all calculate the mass of hydrated compound as,

Mass of Sodium = Na × 2 = 22.99 × 1 = 45.98 g

Mass of Sulfur = S × 1 = 32.06 × 1 = 32.06 g

Mass of Oxygen = O × 14 = 16 × 14 = 224 g

Mass of Hydrogen = H × 20 = 1.01 × 20 = 20.2 g

Mass of Na₂S0₄.10H₂O = 322.24 g

Secondly, calculate mass of water present in hydrated compound. For this one should look for the coefficient present before H₂O in molecular formula of hydrated compound. In this case the coefficient is 10, so the mass of water is...

Mass of water = 10 × 18.02

Mass of water = 180.2 g

Now, we will apply following formula to find percent of water in hydrated compound,

           %H₂O  =  Mass of H₂O / Mass of Hydrated Compound × 100

Putting values,

                                      %H₂O  = 180.2 g / 322.24 g × 100

                                           %H₂O =  55.92 % ≈ 56%

3 0
3 years ago
If an isotope has an atomic number of 8 and a mass number of 18 how many neutrons
Artemon [7]
It will be Oxygen . And total 8 protons, 8 electrons and 9 neutrons are present in it.
6 0
3 years ago
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