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padilas [110]
2 years ago
13

What is the charge of phosphate in AlPO4?

Chemistry
1 answer:
Dennis_Churaev [7]2 years ago
6 0

The charge of phosphate : 3-

<h3>Further explanation</h3>

Oxidation is an increase in oxidation number, while reduction is a reduction in oxidation number.

The formula for determining Oxidation Numbers in general:

1. Single element atomic oxidation number = 0.

Group IA (Li, Na, K, Rb, Cs, and Fr): +1

Group IIA (Be, Mg, Ca, Sr and Ba): +2

Group IIIA(Al, B) : +3

H in compound = +1, except metal hydride compounds (Hydrogen which binds to groups IA or IIA) oxidation number H = -1, for example, LiH, MgH₂, etc.

2. Oxidation number O in compound = -2, except OF2 = + 2 and in peroxide (Na₂O₂, BaO₂) = -1 and superoxide, for example KO₂ = -1/2.

3 The oxidation number in an uncharged compound = 0,

Total oxidation number in ion = ion charge, Example NO₃⁻ = -1

Compound AlPO₄ :

The oxidation number in an uncharged compound = 0

Since the charge of Al as group 3A (or group 13) is +3, while the AlPO₄ compound is a polyatomic compound (consisting of polyatomic ions PO₄ and Al), the PO₄ charge:

charge Al + charge PO₄ = 0

+ 3 + charge PO₄ = 0

<em>charge PO₄ = -3</em>

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7 0
3 years ago
The half-life of radium-226 is 1600 years. How many grams of a 0.25 g sample will remain after 4800 years?
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8 0
3 years ago
An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume, pressure, and temperature were 94 mL,
svet-max [94.6K]

Answer : The initial volume was, 71.2 mL

Explanation :

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1,V_1\text{ and }T_1 are the initial pressure, volume and temperature of the gas

P_2,V_2\text{ and }T_2 are the final pressure, volume and temperature of the gas

We are given:

P_1=0.85atm\\V_1=?\\T_1=66^oC=[66+273]K=339K\\P_2=0.60atm\\V_2=94mL\\T_2=43^oC=[43+273]K=316K

Now put all the given values in above equation, we get:

\frac{0.85atm\times V_1}{339K}=\frac{0.60atm\times 94mL}{316K}

V_1=71.2mL

Therefore, the initial volume was, 71.2 mL

4 0
3 years ago
C is the element symbol for which element?<br>a. Carbon<br>b. Cadmium<br>c. Celenium<br>d. Chlorine​
il63 [147K]

Answer:

A) Carbon

Explanation:

the others are wrong its A

6 0
2 years ago
Read 2 more answers
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