If you were to compare the mass of the products and reactants in a reaction, you would find that the mass of the products is <span>equal to the mass of the reactants.</span>
The percentage of calcium phosphate in ore = 55. 9% so it means each 100g of ore contains 55.9 g of calcium phosphate
The formula of calcium phosphate = Ca3(PO4)3
As per molecular formula each mole of calcium phosphate contains three moles of phosphorous
mass of each mole of calcium phosphate = 310 g
for 31 g of P we need = 310 /3 g of calcium phosphate
= 103.33 g of calcium phosphate
for 1 g of P we need = 103.33 / 31 g of calcium phosphate = 3.33 g
So for 1000g of P we need = 3.33 X 1000g of calcium phosphate
= 3333.3 g of calcium phosphate
now for 55.9 g of Calcium phosphate we need = 100 g of ore
so for 3333.3 g of calcium phosphate we need = 100 X 3333.3 / 55.9 g
= 5963.03
Coal is a fossil fuel, formed from vegetation, which has been consolidated between other rock strata and altered by the combined effects of pressure and heat over millions of years to form coal seams. The energy we get from coal today comes from the energy that plants absorbed from the sun millions of years ago.
Answer:
-1.75
Explanation:
Given
Mass of acid = 10.14g
Mass of water = 511g
Molar mass of the acid = 93.0g/mol
Freezing point = -0.368°C
To get the molality of the solution
Molality = (Number of moles of solute ×1000) / Mass of solvent (g)
Molality = (Mass of solute × 1000) / Molar mass of solute × Mass of solvent (g)
Molality = (10.14g × 1000) /(93.0g/mol × 511g)
= 0.21m
Vant Hoff factor (Ka) is used to calculate the extent of dissociation and it is given by the equation T = i×m×Kf
Where T is change in freezing point of the solution
i is Vant Hoff factor
m is the molality of the solute
Kf is the cryoscopic constant. For water Kf is taken as 1
Therefore
-0.368°C = i × 0.21m × 1
i= -0.368/0.21
= -1.75
(3.5mol)(24.106 g/1mol c6h6) =84.371 g C6H6