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Citrus2011 [14]

3 years ago

10

Which chemical equation below is balanced to correctly represent the Law of Conservation of Mass?

1 answer:

SSSSS [86.1K]3 years ago

7 0

Answer:

The 3rd equation.

Cl2 + 2NaBr —> 2NaCl + Br2

Explanation:

The law of conservation of matter (mass) states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another. This implies that unbalanced chemical equation shows that matter (mass) has been created or destroyed.

Now, we shall determine which equation is balanced as follow:

1. 2Cl2 + NaBr —> 2NaCl + Br2

Reactant >>>>>>>> Product

4 Cl >>>>>>>>>>>> 2 Cl

1 Na >>>>>>>>>>>> 2 Na

1 Br >>>>>>>>>>>> 2 Br

Thus, the equation is not balanced.

2. Cl2 + NaBr —> NaCl + Br2

Reactant >>>>>>>> Product

2 Cl >>>>>>>>>>>> 1 Cl

1 Na >>>>>>>>>>>> 1 Na

1 Br >>>>>>>>>>>> 2 Br

Thus, the equation is not balanced.

3. Cl2 + 2NaBr —> 2NaCl + Br2

Reactant >>>>>>>> Product

2 Cl >>>>>>>>>>>> 2 Cl

2 Na >>>>>>>>>>> 2 Na

2 Br >>>>>>>>>>>> 2 Br

Thus, the equation is balanced.

From the illustration made above only the 3rd equation is balanced. And this is in line with the law of the Conservation of matter (mass) as matter (mass) was not created nor destroyed during the chemical reaction but was transferred to other forms.

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How many moles of PC15 can be produced from 51.0 g of Cl2 (and excess P4)?

slava [35]

Answer:

0.287 mole of PCl5.

Explanation:

We'll begin by calculating the number of mole in 51g of Cl2. This is illustrated below:

Molar mass of Cl2 = 2 x 35.5 = 71g/mol

Mass of Cl2 = 51g

Number of mole of Cl2 =..?

Mole = Mass /Molar Mass

Number of mole of Cl2 = 51/71 = 0.718 mole

Next, we shall write the balanced equation for the reaction. This is given below:

P4 + 10Cl2 → 4PCl5

Finally, we determine the number of mole of PCl5 produced from the reaction as follow:

From the balanced equation above,

10 moles of Cl2 reacted to produce 4 moles of PCl5.

Therefore, 0.718 mole of Cl2 will react to produce = (0.718 x 4)/10 = 0.287 mole of PCl5.

Therefore, 0.287 mole of PCl5 is produced from the reaction.

8 0

3 years ago

The smaller the particle size, the the surface area. Therefore, particle size is to surface area.

levacccp [35]

Answer:

Greater. Inversely proportional

Explanation:

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3 years ago

A certain liquid has a density of 1.50 g ml. 2.00ml of this liquid would have a mass of

VashaNatasha [74]

2ml x 1.5gm^-3 = 3g

8 0

4 years ago

Below is a proposed mechanism for the decomposition of H2O2. H2O2 + I– → H2O + IO– slow H2O2 + IO– → H2O + O2 + I– fast Which of

Savatey [412]

Answer: Option (d) is the correct answer.

Explanation:

The given equations as as follows.

$H_{2}O_{2} + I^{-} \rightarrow H_{2}O + IO^{-}$ (slow)

$H_{2}O_{2} + IO^{-} \rightarrow H_{2}O + O_{2} + I^{-}$

Therefore, overall reaction equation will be as follows.

$2H_{2}O_{2} + I^{-} + IO^{-} \rightarrow 2H_{2}O + O_{2} + IO^{-} + I^{-}$

So, cancelling the spectator ions then the equation will be as follows.

$H_{2}O_{2} \rightarrow 2H_{2}O + O_{2}$

As, it is known that slow step of a reaction is the rate determining step. Therefore, rate law for the slow step will be as follows.

$H_{2}O_{2} + I^{-} \rightarrow H_{2}O + IO^{-}$

Rate law = $k[H_{2}O_{2}][I^{-}]$

Hence, the reaction is first order with respect to $[I^{-}]$ and it is also first order reaction with respect to $[H_{2}O_{2}]$ .

Also, $[I^{-}]$ acts as a catalyst in the reaction.

Thus, we can conclude that the incorrect statement is $IO^{-}$ is a catalyst.

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3 years ago

What is Normal boiling point

loris [4]

Answer: the normal boiling point is the temperature at which the vapour pressure is equal to the standard sea-level atmospheric pressure

Explanation:

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3 years ago

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