Answer:
L=0.85M
Explanation:
ca3 (po4)
66gX1mol/310.18g=2.2178mol/2.5
Answer:
4.06 g BaCl₂
Explanation:
Molarity (M) is given by this formula:
We are given M and L in this equation; we can solve for moles of BaCl₂ and use stoichiometry to convert this amount to grams.
First convert 50.0 mL to L:
Plug this value for L and 0.390 for M into the equation.
Solve for mol by multiplying .05 to both sides.
We have .0195 mol BaCl₂. Now let's use stoichiometry to calculate the amount of grams in .0195 mol BaCl₂.
The molar mass of BaCl₂ is 208.23 g so by using stoichiometry...
There are 4.06 g of BaCl₂ in this solution.
Answer:
The answer to your question is 40 L of NH₃
Explanation:
Data
Volume of NH₃ = x
mass of N₂ = 25 g
mass of H₂ = excess
Balanced chemical reaction
N₂ + 3H₂ ⇒ 2NH₃
Process
1.- Find the molar mass of N₂ and NH₃
N₂ = 14 x 2 = 28g
2NH₃ = 2[ 14 + 3] = 34 g
2.- Write a proportion to solve this problem
28 g of N₂ --------------- 34 g of NH₃
25 g of N₂ ------------- x
x = (25 x 34)/28
x = 30.36 g of NH₃
3.- Calculate the volume of NH₃
17 g of NH₃ -------------- 22.4 L
30.36 g of NH₃ -------- x
x = (30.36 x 22.4) / 17
x = 40 L
0.4575 g of saccharine is present in the ten tablets of saccharine dissolved in water.
From the information in the question, the sulfur in saccharin (C7H5NO3S) was completely converted to sulfate ion (SO4^2-). This ion was now reacted with excess barium chloride to form barium sulfate BaSO4. This later reaction occurs as follows;
SO4^2-(aq) + Ba^2+(aq) --------> BaSO4(s)
Number of moles of BaSO4 obtained = 0.5240 g/233 g/mol
= 0.0025 moles
Since the reaction is 1:1, 0.0025 moles of sulfate ions from saccharine reacted.
Molar mass of saccharine = 7(12) + 5(1) + 14 + 3(16) + 32
= 84 + 5 + 14 + 48 + 32 = 183 g/mol
Mass of saccharine in the tablet = 0.0025 moles × 183 g/mol
= 0.4575 g
Learn more: brainly.com/question/1527403