Question

Saccharin (C7H5NO3S) is sometimes dispensed in tablet form. Ten tablets with total mass of 0.5795 g were dissolved in water. They were oxidized to convert all the sulfur to sulfate ion, which was precipitated by adding an excess of barium chloride solution. The mass of BaSO4 obtained was 0.5240 g. What is the average mass of saccharin per tablet

Answer 1

0.4575 g of saccharine is present in the ten tablets of saccharine dissolved in water.

From the information in the question, the sulfur in saccharin (C7H5NO3S) was completely converted to sulfate ion (SO4^2-). This ion was now reacted with excess  barium chloride to form barium sulfate BaSO4. This later reaction occurs as follows;

SO4^2-(aq) + Ba^2+(aq) --------> BaSO4(s)

Number of moles of BaSO4 obtained = 0.5240 g/233 g/mol

= 0.0025 moles

Since the reaction is 1:1, 0.0025 moles of sulfate ions from saccharine reacted.

Molar mass of saccharine = 7(12) + 5(1) + 14 + 3(16) + 32

= 84 + 5 + 14 + 48 + 32 = 183 g/mol

Mass of saccharine in the tablet = 0.0025 moles × 183 g/mol

= 0.4575 g

Learn more: brainly.com/question/1527403