Answer:
The angular acceleration is 11.66 rad/s²
Explanation:
Step 1: Given data
Three forces are applied to a solid cylinder of mass 12 kg
F1 = 15 N
F2 = 24 N
F3 = 19 N
R2 = 0.22m
R3 = 0.10m
Step 2: Find the magnitude of the angular acceleration
I = ½mr² = ½ * 12kg * (0.22m)² = 0.29 kg*m²
torque τ = I*α
τ = F2*R2 - F1*R1 = 24N*0.22m - 19N*0.10m = 3.38 N*m
This means
I = ½mr² = 0.29 kg*m²
τ = I*α = 3.38 N*m
OR
0.29 kg*m² * α = 3.38 N*m
α = 11.655 rad/s² ≈11.66 rad/s²
The angular acceleration is 11.66 rad/s²
Answer:
Where is the Question?
Explanation:
I am glad to h help you out.
Answer:
A theory or hypothesis does not necessarily provide an accurate scientific explanation to any topic but predicts what can happen.
Explanation:
that would be the energy from the core. because of the fact that ht eearths core is producing 45mill killawhats and giggawats
Answer: the constant angular velocity of the arms is 86.1883 rad/sec
Explanation:
First we calculate the linear velocity of the single sprinkler;
Area of the nozzle = π/4 × d²
given that d = 8mm = 8 × 10⁻³
Area of the nozzle = π/4 × (8 × 10⁻³)²
A = 5.024 × 10⁻⁵ m²
Now total discharge is dived into 4 jets so discharge for single jet will be;
Q_single = Q / n = 0.006 / 4 = 1.5 × 10⁻³ m³/sec
So using continuity equation ;
Q_single = A × V_single
V_single = Q_single/A
we substitute
V_single = (1.5 × 10⁻³) / (5.024 × 10⁻⁵)
V_single = 29.8566 m/s
Now resolving the forces as shown in the second image,
Vt = Vcos30°
Vt = 29.8566 × cos30°
Vt = 25.8565 m/s
Finally we calculate the angular velocity;
Vt = rω
ω_single = Vt / r
from the given diagram, radius is 300mm = 0.3m
so we substitute
ω_single = 25.8565 / 0.3
ω_single = 86.1883 rad/sec
Therefore the constant angular velocity of the arms is 86.1883 rad/sec