For the rest 3 km
Bholu need to run in 5 minutes so
He need to 3 × 1000 / 5 × 60 m/s
3000/ 300 = 10 m/s
So , his speed should be 1 m/s to reach in 5 minute
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The answer is A. <span>Some work input is used to overcome friction. </span>
Answer:
5Hz
Explanation:
Frequency = No. of waves per second
10 waves are produced in 2 seconds
in one second 10/2 waves are produced
(ie) 5 waves are produced in 1 second
Therefore the frequency of wave is 5 Hz
M=F/A
Which means 30 divided by 5 m/s is 6kg(mass)
Answer: he did travel 15 meters.
Explanation:
We have the data:
Acceleration = a = 1.2 m/s^2
Time lapes = 3 seconds
Initial speed = 3.2 m/s.
Then we start writing the acceleration:
a(t) = 1.2 m/s^2
now for the velocity, we integrate over time:
v(t) = (1.2 m/s^2)*t + v0
with v0 = 3.2 m/s
v(t) = (1.2 m/s^2)*t + 3.2 m/s
For the position, we integrate again.
p(t) = (1/2)*(1.2 m/s^2)*t^2 + 3.2m/s*t + p0
Because we want to know the displacementin those 3 seconds ( p(3s) - p(0s)) we can use p0 = 0m
Then the displacement at t = 3s will be equal to p(3s).
p(3s) = (1/2)*(1.2 m/s^2)*(3s)^2 + 3.2m/s*3s = 15m
