Answer:
11m
Explanation:
Wavelength of a wave is the distance between successive crests and trough of a wave. It is represented mathematically as the ratio of the speed of the wave to its frequency. It can be expressed as;
Wavelength ¶ = wave speed (v) /frequency (f)
Given the speed of light c = 2.9979 10^8 m/s.
frequency of the radio wave = 27.075 MHz = 27.075×10^6Hz
Wavelength = 2.9979 10^8/27.075×10^6
Wavelength = 0.11×10^2
Wavelength = 11m
Therefore, the wavelength of the electromagnetic wave being used is 11m
Answer:
The force due to friction is generally independent of the contact area between the two surfaces. This means that even if you have two heavy objects of the same mass, where one is half as long and twice as high as the other one, they still experience the same frictional force when you drag them over the ground.
Explanation:
Independent
The speed of the second satellite is less than the speed of the first satellite.
<h3>What is speed?</h3>
The speed of any moving object is the ratio of the distance covered and the time taken to cover that distance.
Given is a satellite is in a circular orbit around a planet. A second satellite is placed in a different circular orbit that is farther away from the same planet.
When the distance from the center of the orbit increases, the time to complete the orbit will be greater.
Thus, the speed of the second satellite is less than the speed of the first satellite.
Learn more about speed.
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Because the airplane flies at 800 km/h, it will fly 800 km in 1 hour. In order to find how far it travels in 2 hours, we multiply this number by 2. 800*2 = 1600, so the plane will travel 1600 km in 2 hours.
Answer:
v = 8.09 m/s
Explanation:
For this exercise we use that the work done by the friction force plus the potential energy equals the change in the body's energy.
Let's calculate the energy
starting point. Higher
Em₀ = U = m gh
final point. To go down the slope
Em_f = K = ½ m v²
The work of the friction force is
W = fr L cos 180
to find the friction force let's use Newton's second law
Axis y
N - W_y = 0
N = W_y
X axis
Wₓ - fr = ma
let's use trigonometry
sin θ = y / L
sin θ = 11/110 = 0.1
θ = sin⁻¹ 0.1
θ = 5.74º
sin 5.74 = Wₓ / W
cos 5.74 = W_y / W
Wₓ = W sin 5.74
W_y = W cos 5.74
the formula for the friction force is
fr = μ N
fr = μ W cos θ
Work is friction force is
W_fr = - μ W L cos θ
Let's use the relationship of work with energy
W + ΔU = ΔK
-μ mg L cos 5.74 + (mgh - 0) = 0 - ½ m v²
v² = - 2 μ g L cos 5.74 +2 (gh)
v² = 2gh - 2 μ gL cos 5.74
let's calculate
v² = 2 9.8 11 - 2 0.07 9.8 110 cos 5.74
v² = 215.6 -150.16
v = √65.44
v = 8.09 m/s
