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mina [271]
3 years ago
6

What is 10.5g equal to in kg

Chemistry
1 answer:
Natasha2012 [34]3 years ago
8 0
The conversion would be 0.0105 KG.

Hope I helped :)))

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If 0.2 g of nitrobenzene are added to 10.9 g of naphthalene, calculate the molality of the solution. (given: molar mass of nitro
In-s [12.5K]

Molality is defined as 1 mole of a solute in 1 kg of solvent.  

Molality=

\frac{Number of moles of solute}{Mass of solvent in kg}

Number of moles of solute, n=  

\frac{Given mass of the substance}{Molar mass of the substance}

Given mass of the nitrobenzene=0.2 g

Molar mass of the substance= 123.06 g mol⁻¹

Number of moles of nitrobenzene,  

n= \frac{0.2 }{123.06}

Number of moles of nitrobenzene, n= 0.0016  mol

Mass of 10.9 g of naphthalene in kg=0.0109  

Molality= \frac{0.0016}{0.0109 }

Molality= 0.146 m

7 0
3 years ago
What is true of diffusion
Fed [463]

Molecules move from areas of high concentration to areas of low concentration.

7 0
3 years ago
Helpppp nowww plsss!!!
gayaneshka [121]

Answer:

The Sun will appear to rise and set more slowly.

5 0
2 years ago
3) In the reaction below, how many grams of carbon dioxide are produced when iron III
Yanka [14]
<h3>Answer:</h3>

132.03 g

<h3>Explanation:</h3>

<u>We are given;</u>

  • The equation for the reaction as;

Fe₂O₃ + 3CO → 2Fe + 3CO₂

  • Molar masses of CO and CO₂ as 28.01 g/mol and 44.01 g/mol respectively
  • Mass of CO as 84 grams

We are required to calculate the mass of CO₂ that will produced.

<h3>Step 1: Calculate the number of moles of CO</h3>

Moles = Mass ÷ Molar mass

Molar mass of CO = 28.01 g/mol

Therefore;

Moles of CO = 84 g ÷ 28.01 g/mol

                     = 2.9989 moles

                    = 3.0 moles

<h3>Step 2: Calculate the number of moles of CO₂</h3>
  • From the reaction, 3 moles of CO reacts to produce 3 moles of CO₂
  • Therefore; the mole ratio of CO to CO₂ is 1 : 1
  • Hence; Moles of CO = Moles of CO₂

Moles of CO₂ = 3.0 Moles

But; mass = Moles × molar mass

Thus, mass of CO₂ = 3.0 moles × 44.01 g/mol

                                = 132.03 g

Hence, the mass of CO₂ produced from the reaction is 132.03 g

3 0
3 years ago
What is the volume of a gas if 0.182 moles of the gas is at 1.99 atm and 83.4oC?
Pie

\text{Given that,}\\\\\text{Pressure,}~ P = 1.99~ \text{atm}\\ \\\text{No. of moles,}~ n = 0.182~ \text{mol.}\\\\\text{Temperature,}~ T = 83.4^{\circ}~  C = 356.4~K\\\\ \text{Molar gas constant,}~ R = 0.082~ \text{L}~ \text{atm}~ \text{mol}^{-1}~ \text{K}^{-1}\\\\\text{Volume,}~ V =?\\\\\text{We know that,}~\\\\~~~~~~~PV =nRT\\\\\implies V = \dfrac{nRT}{P}\\\\\\~~~~~~~~~~=\dfrac{0.182 \times0.082 \times 356.4 }{1.99}\\\\\\~~~~~~~~~~\approx 2.68~ \text{L.}\\\\\\

\text{Hence the volume of the  gas is 2.68 L.}

6 0
1 year ago
Read 2 more answers
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