Answer:
height = 45 m
Explanation:
Initial velocity = 0 m/s
Final velocity = 30 m/s
Acceleration due to gravity = +10m/s^2 ( because ball is going down )
Using the eqn of motion

where v= final velocity ; u = initial velocity ; g = acceleration due to gravity ; h = height
So,



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Answer:
the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s
Explanation:
Pitot tube

U = velocity(m/s)
= stagnation pressure (pa)
= static pressure (pa)
d = fluid density(kg/m³)

v = true velocity
= 101325 + 1/2(1.225)(25)²


d = 1.225kg/m³

the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s
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