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Kitty [74]
3 years ago
12

Light of wavelength 660 nm passes through two narrow slits 0.65 mm apart. The screen is 2.55 m away. A second source of unknown

wavelength produces its second-order fringe 1.17 mm closer to the central maximum than the 660 nm light. What is the wavelength of the unknown light?
Express your answer to three significant figures and include the appropriate units.
Physics
1 answer:
stiv31 [10]3 years ago
8 0

Answer:

Explanation:

Distance of 2 nd order fringe  x₁ = 2 λ D/d [ λ is wave length , D is distance of screen , d is slit distance.

x₁ = 2 x 660 x10⁻⁹x 2.55/.65 x 10⁻³.= 5.17846 x 10⁻³ m.

Distance of fringe for 2nd radiation = 5.178 x 10⁻³ -1.17 x 10⁻³ = 4.008 x10⁻³

4.008 x 10⁻³ = 2 x λ x 2.55/.65 x 10⁻³

λ = 511 nm approx.

 .

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D. 1.33 segundos.

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El cuerpo es experimenta un movimiento en caída libre al modificarse su velocidad por efecto de la gravitación terrestre. Este cuerpo alcanza instantáneamente el reposo cuando se encuentra a su altura máxima, el tiempo puede obtenerse sabiendo la aceleración y las velocidades incial y final a partir de la siguiente ecuación cinemática:

v = v_{o}+g\cdot t

Donde:

v - Velocidad final del cuerpo, medida en metros por segundo.

v_{o} - Velocidad inicial del cuerpo, medida en metros por segundo.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

t - Tiempo, medido en segundos.

Ahora se despeja el tiempo:

t = \frac{v-v_{o}}{g}

Si v_{o} = 13\,\frac{m}{s}, v=0\,\frac{m}{s} y g = -9.807\,\frac{m}{s^{2}}, entonces:

t = \frac{0\,\frac{m}{s}-13\,\frac{m}{s}}{-9.807\,\frac{m}{s^{2}} }

t = 1.326\,s

Por ende, la respuesta correcta es D.

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