An object having mass m is attached to a spring of force constant k oscillates with simple harmonic motion. The total mechanical
1 answer:
Answer:
The potential energy of the system is .
Explanation:
Given :
Mass of object , m .
Spring constant , k .
Total energy , E .
Maximum displacement , A .
We have to find potential energy when its kinetic energy is equal to 3/4E .
Now, we know :
Total energy is constant in simple harmonic motion.
Therefore ,
Total energy = Kinetic energy + potential energy .
Hence , this is the required solution.
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Answer:
The ratio of the orbital time periods of A and B is
Solution:
As per the question:
The orbit of the two satellites is circular
Also,
Orbital speed of A is 2 times the orbital speed of B
(1)
Now, we know that the orbital speed of a satellite for circular orbits is given by:
where
R = Radius of the orbit
Now,
For satellite A:
Using eqn (1):
(2)
For satellite B:
(3)
Now, comparing eqn (2) and eqn (3):