An object having mass m is attached to a spring of force constant k oscillates with simple harmonic motion. The total mechanical
1 answer:
Answer:
The potential energy of the system is .
Explanation:
Given :
Mass of object , m .
Spring constant , k .
Total energy , E .
Maximum displacement , A .
We have to find potential energy when its kinetic energy is equal to 3/4E .
Now, we know :
Total energy is constant in simple harmonic motion.
Therefore ,
Total energy = Kinetic energy + potential energy .
Hence , this is the required solution.
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Answer:
<em>1.228 x </em><em> mm </em>
<em></em>
Explanation:
diameter of aluminium bar D = 40 mm
diameter of hole d = 30 mm
compressive Load F = 180 kN = 180 x N
modulus of elasticity E = 85 GN/m^2 = 85 x Pa
length of bar L = 600 mm
length of hole = 100 mm
true length of bar = 600 - 100 = 500 mm
area of the bar A = =
= 1256.8 mm^2
area of hole a = =
= 549.85 mm^2
Total contraction of the bar =
total contraction =
==> = <em>1.228 x </em>
<em> mm </em>
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