An object having mass m is attached to a spring of force constant k oscillates with simple harmonic motion. The total mechanical
1 answer:
Answer:
The potential energy of the system is .
Explanation:
Given :
Mass of object , m .
Spring constant , k .
Total energy , E .
Maximum displacement , A .
We have to find potential energy when its kinetic energy is equal to 3/4E .
Now, we know :
Total energy is constant in simple harmonic motion.
Therefore ,
Total energy = Kinetic energy + potential energy .
Hence , this is the required solution.
You might be interested in
Answer:
a) ΔL/L = F / (E A), b) = L (1 + L F /(EA) )
Explanation:
Let's write the formula for Young's module
E = P / (ΔL / L)
Let's rewrite the formula, to have the pressure alone
P = E ΔL / L
The pressure is defined as
P = F / A
Let's replace
F / A = E ΔL / L
F = E A ΔL / L
ΔL / L = F / (E A)
b) To calculate the elongation we must have the variation of the length, so the length of the bar must be a fact. Let's clear
ΔL = L [F / EA]
-L = L (F / EA)
= L + L (F / EA)
= L (1 + L (F / EA))
Answer:8.968 N-m
Explanation:
Given
Length of arm=0.152 m
Downward force=118 N
angle made by arm with vertical
Force can be divided into two components
It's sin component will contribute towards torque while cos component will not contibute
T=8.968 N-m
Assume that the small-massed particle is and the heavier mass particle is
.
Now, by momentum conservation and energy conservation:
Now, there are 2 solutions but, one of them is useless to this question's main point so I excluded that point. Ask me in the comments if you want the excluded solution too.
So now, we see that and
. So therefore, the smaller mass recoils out.
Hope this helps you!
Bye!