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3 years ago

A sector of a circle has a central angle measure of 300°. The diameter of the circle is 26 centimeters.

1 answer:

7 0

The formula is
SA=x/360 multiplied by pi multiplied by the squared radius
So therefore you substitute the values you have into the equation so:
SA= 300/360 x pi x 13 squared (radius is half of diameter so half of 26 is 13)
Therefore the answer should be
442.440
442.4 to one decimal place

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3 years ago

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Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th

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Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 21-1 = 20$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have $T = 2.528$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{0.40}{\sqrt{21}} = 0.0873$

Now, we multiply T and s

$M = 2.528*0.0873 = 0.2207$

Then

The lower end of the interval is the mean subtracted by M. So:

$L = 3.27 - 0.2207 = 3.0493$

The upper end of the interval is the mean added to M. So:

$LCL = 3.27 + 0.2207 = 3.4907$

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

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3 years ago

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Step-by-step explanation:

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3 years ago

The graph of a function, ƒ( x), is plotted on the coordinate plane. Select two of the following functions that would move the gr

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Answer:

The following functions would move the graph of the function to the right on the coordinate plane.

C) $f(x-3)+1$

G) $f(x-5)$

Step-by-step explanation:

We need to check for those functions which shows a horizontal shift of graph to the right.

Translation Rules:

Horizontal shift:

$f(x)\rightarrow f(x+c)$

If $c>0$ the function shifts $c$ units to the left.

If $c$ the function shifts $c$ units to the right.

Vertical shift:

$f(x)\rightarrow f(x)+c$

If $c>0$ the function shifts $c$ units to the up.

If $c$ the function shifts $c$ units to the down.

Applying rules to identify the translation occuring in each of the given functions.

A) $f(x+2)-7$

Translation: $f(x)\rightarrow f(x+2)-7$

The translation shows a shift of 2 units to the left and 7 units down.

B) $f(x)-3$

Translation: $f(x)\rightarrow f(x)-3$

The translation shows a shift of 3 units down.

C) $f(x-3)+1$

Translation: $f(x)\rightarrow f(x-3)+1$

The translation shows a shift of 3 units to the right and 1 units up.

D) $f(x)+4$

Translation: $f(x)\rightarrow f(x)+4$

The translation shows a shift of 4 units up.

F) $f(x+6)$

Translation: $f(x)\rightarrow f(x+6)$

The translation shows a shift of 6 units to the left.

G) $f(x-5)$

Translation: $f(x)\rightarrow f(x-5)$

The translation shows a shift of 5 units to the right.

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3 years ago

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The given ratio of powder to water is 3:2 based on weight for Kool-aide. It is also given that 120g of flavored powder is needed for a certain amount of Kool-aide.

Let us assume that the amount of water (by weight) required to maintain the given ratio of 3:2 be represented by the letter $x$ . Thus, from the given information we can conclude that:

$\frac{Powder Weight}{Water Weight}=\frac{3}{2}=\frac{120}{x}$

$\therefore \frac{3}{2}=\frac{120}{x}$

Cross-multiplying we get:

$3x=240$

$\therefore x=\frac{240}{3}=80$ grams.

Thus, the amount of water in grams in that Kool-aide is 80 grams.

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