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Schach [20]
3 years ago
9

You have two wires made of two different metals (metal A and metal B). Both wires are the same thickness and length. In one circ

uit, you use the metal A wire. In another identical circuit, you use the metal B wire. The metal A wire gets hot, while the metal B wire does not. Explain
Chemistry
1 answer:
kotegsom [21]3 years ago
7 0

Answer: we don't have enough information to answer.

Explanation:

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There are 64 pretzels in a 16-ounce bag how many proportion would be in a 5-ounce bag?
qwelly [4]

Answer:

20 pretzels.

Explanation:

So in the first bag there at 64 pretzels in 16-ounces.

We can divide both these numbers by 16, to get 4 pretzels per ounce.

If we multiply both numbers by 5, we get 20 pretzels per ounces.

So, 20 pretzels i5-ounce bag.

3 0
3 years ago
If a compound has a log kow value of 6.5, what would be its predicted concentration (in ppm) in the fat of fish that swim in wat
blsea [12.9K]
Easy ans I don't know .......
5 0
4 years ago
An electron has the properties of a _____ and ______
Dennis_Churaev [7]

Answer:

mass, and spin

Explanation:

8 0
3 years ago
What is the wavelength in picometers for an electron with 360 eV of kinetic energy?
Rom4ik [11]

Answer:

Wavelength = 64.635 pm

Explanation:

The expression for the deBroglie wavelength and kinetic energy is:

\lambda=\frac {h}{\sqrt{2\times m\times K.E.}}

Where,  

\lambda is the deBroglie wavelength  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

m is the mass of electron having value 9.11\times 10^{-31}\ kg

K.E. is the kinetic energy of the electron.

Given, K.E. = 360 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.6022 × 10⁻¹⁹ J

So, K.E. = 360\times 1.6022\times 10^{-19}\ J=5.76792\times 10^{-17}\ J

Applying in the equation as:

\lambda=\frac {h}{\sqrt{2\times m\times K.E.}}

\lambda=\frac{6.626\times 10^{-34}}{\sqrt {{2\times 9.11\times 10^{-31}\times 5.76792\times 10^{-17}}}}\ m

\lambda=\frac{10^{-34}\times \:6.626}{\sqrt{10^{-48}\times \:105.0915024}}\ m

\lambda=6.4635\times 10^{-11}\ m

Also, 1 m = 10¹² pm

<u>So, Wavelength = 64.635 pm</u>

4 0
4 years ago
What kind of bond would you find between two alike oxygen atoms
IRISSAK [1]

Answer:

Covalent bond

Explanation:

3 0
3 years ago
Read 2 more answers
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