Answer:
Q = 16163.88 Joules
Explanation:
Given the following data;
Initial temperature, T1 = -25°C
Final temperature, T2 = 150°C
Mass = 45.5 g
Specific heat capacity of ice = 2.03 J/g°C
To find the quantity of heat required;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 150 - (-25)
dt = 150 + 25
dt = 175°C
Substituting into the formula, we have;
Q = 16163.88 Joules
x = 20 long tables
y = 5 round table
Explanation:
We have the following system of equations:
x + y = 25
8x + 6y = 190
From the first equation we have:
x = 25 - y
And we replace x in the second equation:
8(25 - y) + 6y = 190
200 - 8y + 6y = 190
200 - 2y = 190
200 - 190 = 2y
10 = 2y
y = 5
Now we insert the value of y in the next equation:
x = 25 - y
x = 25 - 5
x = 20
Learn more about:
system of equations
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The four steps of food safety are:
- Clean: Wash your hands and clean surfaces often
- Separate: Don't cross-contaminate the food
- Cook: Cook the food to the right temperature
- Chill: Refrigerate promptly
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Answer:
B. Green solution density is 1.06 g/ml and blue solution density is 1.20 g/ml
Explanation:
Density is given as,
D = Mass / Volume
Red Solution,
D = 25 g / 25 mL
D = 1 g/mL
Green Solution,
D = 26.5 g / 25 mL
D = 1.06 g/mL
Yellow Solution,
D = 28.2 g / 25 mL
D = 1.128 g/mL
Blue Solution,
D = 30 g / 25 mL
D = 1.20 g/mL
D water expands when it freezes
