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mr_godi [17]
3 years ago
14

What multiplies to 26 and adds to 23

Mathematics
1 answer:
svp [43]3 years ago
8 0
The two numbers that adds up to 23 and mutliplies to 26 are 1.19 and 21.808.

21.808 + 1.19 ≈ 23
21.808 × 1.19 ≈ 26
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A store owner recorded the number of tickets sold each hour. the graph shows some of the store owners data what is the slope of
Shalnov [3]

Answer: B 2

Step-by-step explanation:

If you look at the graph, you can see it goes up every hour by 2.

So therefore your answer will be 2.

Hope this helps!

7 0
3 years ago
Read 2 more answers
If two fair dice are rolled, what is the probability that the total showing is either even or less than five?
snow_tiger [21]

The Probability that the total showing is either even or less than five = 5/6

<h3>What is Probability?</h3>

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. The probability of an event is a number between 0 and 1, where, broadly speaking, 0 represents the event's impossibility and 1 implies certainty.

<h3>According to the given data:</h3>

The example space for rolling two dice is:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

36 events total.

Events that have a sum that is even or less than Five .

Total instances when the aggregate is even or less than Five equals 30.

P(sum is even or less than 5)

= (Total no of favorable event)/(Total no of event)

= 30/36

=5/6

probability that the total showing is either even or less than five = 5/6

To know more about probability visit :

brainly.com/question/13066369

#SPJ4

6 0
1 year ago
Elizabeth has $10, $5, and $1 bills worth $101. she has five more five dollar bills than ten dollar bills and 4 times more 1 dol
vesna_86 [32]

Let x be number of $10 dollar bills

Let y be number of $5 dollar bills

Let z be number of $1 dollar bills

From the question, we can come up with three equations (so we can find the values of x, y & z) :

  • 10x + 5y + z = 101
  • y - x = 5
  • z = 4x

The first equation comes from finding the total money Elizabeth has, which is $101.

The second equation comes from value of y (number of $5 bills) is more than value of x (number of $10 bills) by 5 dollars.

The third equation comes from the value of z (number of $1 bills) being 4 times more than the value of x (number of $10 bills).

Now, we will begin to find the value of x, y & z.

From the first equation,

10x + 5y + z = 101

Substitute the third equation (z = 4x) into z:

10x + 5y + 4x = 101

Simplify this and you get,

14x + 5y = 101

Now, we use the second equation. The second equation is y - x = 5. If we try to make y as the subject, it becomes y = 5 + x.

Now, substitute this into the value of y of the last working we did:

14x + 5(5+x) = 101

Simplify that and it becomes:

x = 4

Then, substitute this value of x into the second and third equations to find y and z.

y - x = 5

y - 4 = 5

y = 9

z = 4x

z = 4(4)

z = 16

Finally, let's check these answers by substituting them into the first equation to try and see if the total value is <em>really</em> $101.

10x + 5y + z = 10(4) + 5(9) + 16

10x + 5y + z = 40 + 45 + 16

10x + 5y + z = 101

Thus, our answers are correct. Elizabeth has FOUR $10 bills, NINE $5 bills and SIXTEEN $1 bills.

6 0
3 years ago
Read 2 more answers
1. Show that
Eddi Din [679]

Answer:

 (10a+5)²= 100 a( a+1) + 25

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given

     (10a+5)²

By using (a+b)² = a² +2ab +b²

                   = (10a)²+ 2 × 10a× 5 + (5)²

                   = 100a² + 100a + 25

                   = 100 a( a+1) + 25

6 0
2 years ago
Determine the number of solutions for the quadratic function f(x) = -x^2 + 3x - 9.
Setler79 [48]

Answer:

0

Step-by-step explanation:

Rewrite the equation as x^2-3x+9=0

find the determinant.

D = b^2-4ac = (-3)^2-4*1*9 <0

no solution

7 0
3 years ago
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