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Vikki [24]
3 years ago
9

What Element has a -4 oxidation number.

Chemistry
1 answer:
otez555 [7]3 years ago
4 0
Carbon.................
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A theory does not change into a scientific law with the accumulation of new or better evidence. A theory will always remain a theory
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When a aqueous solution of a certain acid is prepared, the acid is dissociated. Calculate the acid dissociation constant of the
stepan [7]
<h2>K_a = \dfrac{[H^{+}] [A^{-}]}{[HA]}</h2>

Explanation:

  • When an aqueous solution of a certain acid is prepared it is dissociated is as follows-

        {\displaystyle {\ce {HA  ⇄  {H^+}+{A^{-}}}  }}

Here HA is a protonic acid such as acetic acid, CH_3COOH

  • The double arrow signifies that it is an equilibrium process, which means the dissociation and recombination of the acid occur simultaneously.
  • The acid dissociation constant can be given by -

        K_a = \dfrac{[H^{+}] [A^{-}]}{[HA]}

  • The reaction is can also be represented by Bronsted and lowry -

         \\{\displaystyle {\ce {{HA}+ H_2O} ⇄  [H_3O^+] [A^-]

  • Then the dissociation constant will be

        K_a = \dfrac{[H_3O^{+}] [A^{-}]}{[HA]}

Here, K_a is the dissociation constant of an acid.

6 0
4 years ago
a balloon is filled with 3.60 L of H2 gas at STP. If the balloon is taken into the sea where the pressure is 2.50 atm and the te
kherson [118]

The new volume of the hydrogen gas in the balloon is 1.5 L.

<u>Explanation:</u>

At STP, Temperature, T1 is 0° C = 0 + 273 K = 273 K

Pressure, P1 = 1 atm

Here given volume, V1 = 3.60 L

Balloon at sea,

Pressure, P2 = 2.5 atm

Temperature, T2 = 10° C = 10 + 273 = 283 K

Volume, V2 = ?

Here, we have to use the equation,

$\frac{P1V1}{T1} = \frac{P2V2}{T2}

We have to rearrange the equation to get V2 as,

$V2 = \frac{P1V1T2}{T1P2}

Now plugin the values as,

V2 = $\frac{1 atm \times 3.6 L \times 283 K}{273 K \times 2.5}

   = 1.5 L

So the new volume of the hydrogen gas is 1.5 L.

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: A ____________ is an arrow that shows the strength and direction of a force.
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Explanation:

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