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charle [14.2K]
3 years ago
14

The genes for alpha-goblin and beta-globin are found:\

Physics
2 answers:
Luba_88 [7]3 years ago
5 0
Actually the third one is introns, trust me I did the test 
BabaBlast [244]3 years ago
3 0

<em><u>Globin is the protein part of hemoglobin. </u></em>

<u>The alpha globin family </u><u>is located on chromosome 16.</u>

<u>The beta globin family</u> <em><u>is located on chromosome 11.</u></em>

<em><u>The answer is</u></em>: <u>d.) On different chromosomes. </u>

-------------

<u>The vast majority of genes encoding a protein encoded</u> <em><u>within the nucleus of metazoan cells</u></em> <u>contain both introns and exons. </u>

<em><u>The answer is</u></em>: <u>b.) both exons and introns. </u>

-----------------

<u><em>In the DNA sequence the coding content of a gene is not continuously distributed along said gene</em></u>, <u>but has discontinuities, called introns, whose sequence does not encode proteins</u>.

<em><u>The answer is</u></em>: <u>a.) Intron. </u>

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What do you mean by resistance of conductor?state it’s unit.
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Answer:

its unit is Ohm

Explanation:

Resistance means material which resist the passing current  through it and the value of resistance says how much the material is resisting the current and it temperature dependent and the unit is Ohm.

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3 years ago
What is the main function of a protein within the body?
aksik [14]
The answer looks to be "A" because Protein is used to regulate organs.
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Eric has a mass of 70 . He is standing on a scale in an elevator that is accelerating downward at 1.7 . What is the approximate
pychu [463]

Answer:

B)

Explanation:

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The forces on Eric are his weight (downward) and this normal force (upward), so we can write the net force over him as (also using Newton's 2nd Law):

F=W-N=ma

which means

N=W-ma=mg-ma=m(g-a)

and for our values this is:

N=mg-ma=(70kg)(9.8m/s^2-1.7m/s^2)=567N

5 0
3 years ago
The Franck-Hertz experiment involved shooting electrons into a low-density gas of mercury atoms and observing discrete amounts o
Anuta_ua [19.1K]

Answer:

the final kinetic energy is 0.9eV

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you can assume that the shot electron excites the electron of the hydrogen atom to the first excited state, that is

E_{n_2-n_1}=-13.6eV[\frac{1}{n_2^2}-\frac{1}{n_1^2}]\\\\E_{2-1}=-13.6eV[\frac{1}{2^2}-\frac{1}{1}]=-10.2eV

-10.2eV is the energy that the shot electron losses in the excitation of the electron of the hydrogen atom. Hence, the final kinetic energy of the shot electron after it has given -10.2eV of its energy is:

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3 years ago
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zaharov [31]

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