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Eddi Din [679]
3 years ago
14

Calculate the mass of 25,000 molecules of nitrogen gas. (1 mole = 6.02 x 1023 molecules)

Chemistry
2 answers:
Ainat [17]3 years ago
7 0

Hey there!

Molar mass N2 = 28.01 g/mol

Therefore:

28.01 g N2 -------------- 6.02*10²² molecules N2

( mass N2 ?? ) ----------- 25,000 molecules N2

mass N2 =  ( 25,000 * 28.01 ) /  ( 6.02*10²³ )

mass N2 = 700250 / 6.02*10²³

mass N2 = 1.163*10⁻¹⁸ g


Hope that helps!

Alekssandra [29.7K]3 years ago
5 0

Answer: 116.2\times 10^{-26} grams

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text {Given molecules}}{\text {Avogadros number}}

\text{Number of moles}=\frac{25000}{6.023\times 10^{23}}=4.15\times 10^{-26}moles  

Now 1 mole of N_2 gas weighs = 28 grams

4.15\times 10^{-26}moles of N_2 gas weighs =\frac{28}{1}\times 4.15\times 10^{-26}=116.2\times 10^{-26} grams

Thus the mass will be 116.2\times 10^{-26} grams.

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From the question we are told

A solution made by mixing 20.0 g of a non-volatile compound with 125 mL of water at 25°C has a vapor pressure of 22.67 torr. What is the molecular weight (3sf) of the compound (g/mol).

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